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17) Imagine the recessive allele of gene B above is a beneficial trait for individuals of the species to have, but the recessive allele of the C gene is detrimental. Imagine also, you only have two individuals from which you wish to build a successful population: one is homozygous dominant for the two genes and the other homozygous recessive for the two genes. Considering the table of recombination rates above, if you mate these two individuals, what percentage of the resulting offspring will have both beneficial alleles? 18) Theoretically speaking, we should not be able to observe a recombination rate greater than 50%. Why is this so? If we measure a recombination rate of 50% what does it mean? 19) Create a chromosome linkage map for the seven genes provided. Numbers represent the recombination rates among offspring who have parents who are each pure-bred for the alleles of genes described. Assuming the gene for eye color is 25 map units from the end of the chromosome, provide a list of the seven genes in order from the end of the chromosome and include the distance each gene is from the end of the chromosome (from point 0.0). Genes: Claw Length (CL), Growth Rate (GR), Fur Length (FL), Posture (P), Eye Color (EC), Number of Scales (S), and Number of Toes (T). CL-GR=4.3 CL-FL=7.0 GR-FL=11.3 GR-P=10.9 CL-P=15.2 CL-EC-3.1 CL-S=3.5 GR-EC = 1.2 GR-S=0.8 GR-T=8.1 EC-S=0.4 EC-T=7.9 CL-T4.8 FL-P=22.2 FL-EC=10.1 P-EC=12.1 P-S=11.7 S-T=8.3 FL=S=10.5 P=T=20.0 FL-T=2.2

17) Imagine the recessive allele of gene B above is a beneficial trait for individuals of the species to have, but the recessive allele of the C gene is detrimental. Imagine also, you only have two individuals from which you wish to build a successful population: one is homozygous dominant for the two genes and the other homozygous recessive for the two genes. Considering the table of recombination rates above, if you mate these two individuals, what percentage of the resulting offspring will have both beneficial alleles? 18) Theoretically speaking, we should not be able to observe a recombination rate greater than 50%. Why is this so? If we measure a recombination rate of 50% what does it mean? 19) Create a chromosome linkage map for the seven genes provided. Numbers represent the recombination rates among offspring who have parents who are each pure-bred for the alleles of genes described. Assuming the gene for eye color is 25 map units from the end of the chromosome, provide a list of the seven genes in order from the end of the chromosome and include the distance each gene is from the end of the chromosome (from point 0.0). Genes: Claw Length (CL), Growth Rate (GR), Fur Length (FL), Posture (P), Eye Color (EC), Number of Scales (S), and Number of Toes (T). CL-GR=4.3 CL-FL=7.0 GR-FL=11.3 GR-P=10.9 CL-P=15.2 CL-EC-3.1 CL-S=3.5 GR-EC = 1.2 GR-S=0.8 GR-T=8.1 EC-S=0.4 EC-T=7.9 CL-T4.8 FL-P=22.2 FL-EC=10.1 P-EC=12.1 P-S=11.7 S-T=8.3 FL=S=10.5 P=T=20.0 FL-T=2.2

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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17) Imagine the recessive allele of gene B above is a beneficial trait for individuals of the species to have, but the recessive allele of the C gene is detrimental. Imagine also, you only have two individuals from which you wish to build a successful population: one is homozygous dominant for the two genes and the other homozygous recessive for the two genes. Considering the table of recombination rates above, if you mate these two individuals, what percentage of the resulting offspring will have both beneficial alleles? 18) Theoretically speaking, we should not be able to observe a recombination rate greater than 50%. Why is this so? If we measure a recombination rate of 50% what does it mean? 19) Create a chromosome linkage map for the seven genes provided. Numbers represent the recombination rates among offspring who have parents who are each pure-bred for the alleles of genes described. Assuming the gene for eye color is 25 map units from the end of the chromosome, provide a list of the seven genes in order from the end of the chromosome and include the distance each gene is from the end of the chromosome (from point 0.0). Genes: Claw Length (CL), Growth Rate (GR), Fur Length (FL), Posture (P), Eye Color (EC), Number of Scales (S), and Number of Toes (T). CL-GR=4.3 CL-FL=7.0 GR-FL=11.3 GR-P=10.9 CL-P=15.2 CL-EC-3.1 CL-S=3.5 GR-EC = 1.2 GR-S=0.8 GR-T=8.1 EC-S=0.4 EC-T=7.9 CL-T4.8 FL-P=22.2 FL-EC=10.1 P-EC=12.1 P-S=11.7 S-T=8.3 FL=S=10.5 P=T=20.0 FL-T=2.2
Transcribed Image Text:17) Imagine the recessive allele of gene B above is a beneficial trait for individuals of the species to have, but the recessive allele of the C gene is detrimental. Imagine also, you only have two individuals from which you wish to build a successful population: one is homozygous dominant for the two genes and the other homozygous recessive for the two genes. Considering the table of recombination rates above, if you mate these two individuals, what percentage of the resulting offspring will have both beneficial alleles? 18) Theoretically speaking, we should not be able to observe a recombination rate greater than 50%. Why is this so? If we measure a recombination rate of 50% what does it mean? 19) Create a chromosome linkage map for the seven genes provided. Numbers represent the recombination rates among offspring who have parents who are each pure-bred for the alleles of genes described. Assuming the gene for eye color is 25 map units from the end of the chromosome, provide a list of the seven genes in order from the end of the chromosome and include the distance each gene is from the end of the chromosome (from point 0.0). Genes: Claw Length (CL), Growth Rate (GR), Fur Length (FL), Posture (P), Eye Color (EC), Number of Scales (S), and Number of Toes (T). CL-GR=4.3 CL-FL=7.0 GR-FL=11.3 GR-P=10.9 CL-P=15.2 CL-EC-3.1 CL-S=3.5 GR-EC = 1.2 GR-S=0.8 GR-T=8.1 EC-S=0.4 EC-T=7.9 CL-T4.8 FL-P=22.2 FL-EC=10.1 P-EC=12.1 P-S=11.7 S-T=8.3 FL=S=10.5 P=T=20.0 FL-T=2.2
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