17 cm 0.45 kg 76 cm 0.65 kg A 50 g meter stick is balanced at its midpoint (50-cm). Then a 0.45 kg and a 0.65 kg mass are suspended, using light strings, from the 17 cm and 76 cm points as shown above. a. What are the force(s) acting on the meter stick at the pivot point location (50-cm)? What are their magnitudes? Submission type: Submit entries below as answer to receive credit Save entries below (not submitted for credit yet) Rich formatting >> The forces acting on the meter stick at the pivot point are the weight forces on the first block (4.41N), the second block (6.37N), and the stick itself (0.49N). Finally, there is also the normal force from the pivot onto the stick (11.27N). Submit Answer Your submission has been recorded. Tries 1/10 Previous Tries Calculate the magnitude of the torque acting on the board about an axis pointing out of the page (screen) at the following points (all points measured from the leftmost side of the beam): b. the 0-cm point. Submit Answer Incorrect. Tries 5/10 Previous Tries c. the 50-cm point. Submit Answer Tries 0/10 d. the 100-cm point. Submit Answer Tries 0/10

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17 cm
0.45 kg
76 cm
0.65 kg
A 50 g meter stick is balanced at its midpoint (50-cm). Then a 0.45 kg and a 0.65 kg mass are suspended, using light strings, from the 17 cm and 76 cm points as shown above.
a. What are the force(s) acting on the meter stick at the pivot point location (50-cm)? What are their magnitudes?
Submission type:
Submit entries below as answer to receive credit
Save entries below (not submitted for credit yet)
Rich formatting >>
The forces acting on the meter stick at the pivot point are the weight forces on
the first block (4.41N), the second block (6.37N), and the stick itself (0.49N).
Finally, there is also the normal force from the pivot onto the stick (11.27N).
Submit Answer Your submission has been recorded. Tries 1/10 Previous Tries
Calculate the magnitude of the torque acting on the board about an axis pointing out of the page (screen) at the following points (all points measured from the leftmost side of the beam):
b. the 0-cm point.
Submit Answer Incorrect. Tries 5/10 Previous Tries
c. the 50-cm point.
Submit Answer Tries 0/10
d. the 100-cm point.
Submit Answer Tries 0/10
Transcribed Image Text:17 cm 0.45 kg 76 cm 0.65 kg A 50 g meter stick is balanced at its midpoint (50-cm). Then a 0.45 kg and a 0.65 kg mass are suspended, using light strings, from the 17 cm and 76 cm points as shown above. a. What are the force(s) acting on the meter stick at the pivot point location (50-cm)? What are their magnitudes? Submission type: Submit entries below as answer to receive credit Save entries below (not submitted for credit yet) Rich formatting >> The forces acting on the meter stick at the pivot point are the weight forces on the first block (4.41N), the second block (6.37N), and the stick itself (0.49N). Finally, there is also the normal force from the pivot onto the stick (11.27N). Submit Answer Your submission has been recorded. Tries 1/10 Previous Tries Calculate the magnitude of the torque acting on the board about an axis pointing out of the page (screen) at the following points (all points measured from the leftmost side of the beam): b. the 0-cm point. Submit Answer Incorrect. Tries 5/10 Previous Tries c. the 50-cm point. Submit Answer Tries 0/10 d. the 100-cm point. Submit Answer Tries 0/10
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