16% of all college students volunteer their time. Is the percentage of college students who are volunteerslarger for students receiving financial aid? Of the 381 randomly selected students who receive financial aid, 72of them volunteered their time. What can be concluded at the a = 0.10 level of significance?a. For this study, we should use Select an answerb. The null and alternative hypotheses would be:Ho: ? îSelect an answer(please enter a decimal)H₁: ?Select an answer ↑(Please enter a decimal)c. The test statistic ?î =(please show your answer to 3 decimal places.)d. The p-value =(Please show your answer to 4 decimal places.)e. The p-value is ? ŷ αf. Based on this, we shouldSelect an answer the null hypothesis.g. Thus, the final conclusion is that ...The data suggest the populaton proportion is significantly higher than 16% at a = 0.10, so there issufficient evidence to conclude that the percentage of financial aid recipients who volunteer ishigher than 16%.The data suggest the population proportion is not significantly higher than 16% at a = = 0.10, sothere is sufficient evidence to conclude that the percentage of financial aid recipients whovolunteer is equal to 16%.The data suggest the population proportion is not significantly higher than 16% at a = 0.10, sothere is insufficient evidence to conclude that the percentage of financial aid recipients whovolunteer is higher than 16%.

The claim is that the % of college students who are volunteers larger for students receiving…

Answered: 16% of all college students volunteer…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

In a study of the accuracy of fast food drive-through orders, one restaurant had 32 orders that were not accurate among 360 orders observed. Use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable? Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p#0.1 H,:p=0.1 О в. Но: р30.1 H1:p>0.1 с. Но: р30.1 H,: p 0.1 O D. Ho: p=0.1 H:p<0.1 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.)
Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 5973 patients treated with this drug, 153 developed the adverse reaction of nausea. Use a 0.10 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction? ... Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p=0.03 H:p0.03 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.)
Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6208 patients treated with this drug, 159 developed the adverse reaction of nausea. Use a 0.05 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction? Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p= 0.03 H1: p>0.03 O B. Ho: p#0.03 H;:p= 0.03 OC. Ho: p=0.03 H1: p#0.03 O D. Ho: p= 0.03 H1: p<0.03 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is. (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Hn. There is not sufficient evidence to warrant rejection of the claim that 3% of users develop nausea. O B. Reject Hn. There is…
14% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 362 randomly selected students who receive financial aid, 36 of them volunteered their time. What can be concluded at the � = 0.05 level of significance? Use the p-value approach. For this study, we should use z-test for a population proportion or t-test for a population mean The null and alternative hypotheses would be: �0: (p or u) (please enter a decimal) �1: (p or u) (Please enter a decimal) The test statistic (z or t) = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ( > or < with line) � Based on this, we should (accept or reject or fail to reject) the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly lower than 14% at � =…
Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 6103 patients treated with this drug, 151 developed the adverse reaction of nausea. Use a 0.05 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction? Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Ho: p= 0.03 %3D H1:p0.03 D. Ho: p= 0.03 %3D H1:p#0.03 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is - 2.43 . (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.)
Before the semester began, Professor Keithley predicted that 15% of hisphilosophy students would receive an A, 30% a B, 40% a C, 10% a D, and 5%an F. At the end of the semester, 14 of Professor Keithley’s philosophy studentsearned an A, 19 a B, 12 a C, 5 a D, and 2 an F.Use the Chi-Square test and a 0.05 level of significance to determine if ProfessorKeithley’s predicted percentages were accurate. (State your null and alternativehypothesis, find the critical values and test statistics, make a decision, and writea conclusion based on your results).
I need help asap. This is the question. A recent study at a local college claimed that the porportion, p, of students who commute more than 15 miles to school is no more than 15% . If a random sample of 175 students at this college is selected, and it is found that 86 commute more than 15 miles to school, can we reject the college's claim at the 0.05 level of significance. Perform 1 failed test then fill in the table below
Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 74 bpm. Use a 0.01 significance level. E Click the icon to view the pulse rate data. Pulse Rate Data Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? Pulse Rate (bpm) O A. Ho: H= 74 bpm H1: H 74 bpm 57 35 104 86 ОС. Но: и» 74 bpm H1: µ<74 bpm O D. Ho: H=74 bpm H1: µ+74 bpm 97 101 62 49 59 73 Determine the test statistic. 69 45 104 42 |(Round to two decimal places as needed.) 52 105 99 36 Determine the P-value. 74 54 (Round to three decimal places as needed.) 105 60 56 82 State the final conclusion that addresses the original claim. 88 75 52 59 V Ho. There is evidence to conclude that the mean of the population of pulse rates for adult females is V 74 bpm. 82 104 97 76 76 47 97 74 63 52 93 98 104 53 35 35 100 39 Click to select your answer(s). 58 41
Find the P-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.05 significance level. Is the alternative hypothesis supported? z=2.6 for Hoμ=149 pounds and H₂: μ* 149 pounds
18% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 379 randomly selected students who receive financial aid, 57 of them volunteered their time. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for a population proportion b. The null and altemative hypotheses would be: Họ: P (please enter a decimal) Hi: P (Please enter a decimal) c. The test statistic zv (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is > v f. Based on this, we should fail to reject g. Thus, the final conclusion is that ... a the null hypothesis. O The data suggest the population proportion is not significantly lower than 18% at a = 0.01, so there is sufficient evidence to conclude that the percentage of financial aid recipients who volunteer is equal to 18%. O The data suggest the…
Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 55% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.2616. a. State a conclusion about the null hypothesis. (Reject H, or fail to reject Hn.) Choose the correct answer below. O A. Reject H, because the P-value is less than or equal to a. O B. Reject H, because the P-value is greater than a. OC. Fail to reject H, because the P-value is greater than a. O D. Fail to reject H, because the P-value is less than or equal to a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? O A. There is not sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 55%. O B. There is sufficient evidence to support…
A medical equipment manufacturer believes that the proportion of faulty blood pressure monitors is greater than 0.11, the proportion stated by the supplier. We perform a hypothesis test at a significance level of 0.05 with the null and alternative hypothesis as follows: Ho: p = 0.11 and Ha: p < 0.11. A researcher inspects 150 items and finds 25 faulty ones. She gives a p-value of 0.01 in her analysis. Which of the following definitions is the correct interpretation of the p-value? O The probability of getting 25 or more faulty blood pressure monitors out of 150 if the true faulty rate is 0.11. The value that the z-statistic must be less than in order to reject the null hypothesis. The probability of rejecting a true null hypothesis. O The probability that the true rate of faulty items is 0.01.

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