16% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 398 people from the inner city surveyed, 52 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01?For this study, we should use Z TEST FOR A POPULATION PROPORTIONThe null and alternative hypotheses would be: Ho: P=0.15 (please enter a decimal) H1: P <0.13. The test statistic _z__ = _______ (please show your answer to 3 decimal places.)4. The p-value = __0.0144__ (Please show your answer to 4 decimal places.)5. The p-value is __<__α6. Based on this, we should ___FAIL TO REJECT___ the null hypothesis.Thus, the final conclusion is that ...The data suggest the populaton proportion is significantly smaller than 16% at αα = 0.01, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 16%The data suggest the population proportion is not significantly smaller than 16% at αα = 0.01, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 16%.The data suggest the population proportion is not significantly smaller than 16% at αα = 0.01, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 16%.Interpret the p-value in the context of the study. There is a 16% chance of a Type I errorIf the population proportion of inner city residents who have sleep apnea is 16% and if another 398 inner city residents are surveyed then there would be a 5.51% chance fewer than 13% of the 398 residents surveyed have sleep apnea.There is a 5.51% chance that fewer than 16% of all inner city residents have sleep apnea.If the sample proportion of inner city residents who have sleep apnea is 13% and if another 398 inner city residents are surveyed then there would be a 5.51% chance of concluding that fewer than 16% of inner city residents have sleep apnea.Interpret the level of significance in the context of the study.There is a 1% chance that the proportion of all inner city residents who have sleep apnea is smaller than 16%.There is a 1% chance that aliens have secretly taken over become repeat offenders is lower than 15% and if another 397 convicted sex offender drug addicts are observed then there would be a 10% chance that we would end up falsely concluding that the proportion of all convicted sex offender drug addicts who become repeat offenders is equal to 15%.There is a 10% chance that the proportion of all convicted sex offender drug addicts who become repeat offenders is lower than 15%.If the population proportion of convicted sex offender drug addicts who become repeat offenders is 15% and if another 397 convicted sex offender drug addicts are observed, then there would be a 10% chance that we would end up falsely concluding that the proportion of all convicted sex offender drug addicts who become repeat offenders is lower than 15%.

Given that n=398 , X=52 , p=16%=0.16 Note: According to bartleby experts question answers…

Answered: 16% of all Americans suffer from sleep…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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16% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 398 people from the inner city surveyed, 52 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01?

For this study, we should use Z TEST FOR A POPULATION PROPORTION
The null and alternative hypotheses would be:
Ho: P=0.15 (please enter a decimal)
H₁: P <0.1

3. The test statistic _z__ = _______ (please show your answer to 3 decimal places.)

4. The p-value = __0.0144__ (Please show your answer to 4 decimal places.)

5. The p-value is __<__α

6. Based on this, we should ___FAIL TO REJECT___ the null hypothesis.

Thus, the final conclusion is that ...
- The data suggest the populaton proportion is significantly smaller than 16% at αα = 0.01, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 16%
- The data suggest the population proportion is not significantly smaller than 16% at αα = 0.01, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 16%.
- The data suggest the population proportion is not significantly smaller than 16% at αα = 0.01, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 16%.
Interpret the p-value in the context of the study.
- There is a 16% chance of a Type I error
- If the population proportion of inner city residents who have sleep apnea is 16% and if another 398 inner city residents are surveyed then there would be a 5.51% chance fewer than 13% of the 398 residents surveyed have sleep apnea.
- There is a 5.51% chance that fewer than 16% of all inner city residents have sleep apnea.
- If the sample proportion of inner city residents who have sleep apnea is 13% and if another 398 inner city residents are surveyed then there would be a 5.51% chance of concluding that fewer than 16% of inner city residents have sleep apnea.
Interpret the level of significance in the context of the study.
- There is a 1% chance that the proportion of all inner city residents who have sleep apnea is smaller than 16%.
- There is a 1% chance that aliens have secretly taken over become repeat offenders is lower than 15% and if another 397 convicted sex offender drug addicts are observed then there would be a 10% chance that we would end up falsely concluding that the proportion of all convicted sex offender drug addicts who become repeat offenders is equal to 15%.
- There is a 10% chance that the proportion of all convicted sex offender drug addicts who become repeat offenders is lower than 15%.
- If the population proportion of convicted sex offender drug addicts who become repeat offenders is 15% and if another 397 convicted sex offender drug addicts are observed, then there would be a 10% chance that we would end up falsely concluding that the proportion of all convicted sex offender drug addicts who become repeat offenders is lower than 15%.

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