162%= z3(8A+4C+2D)+zY-6A+: +=(A-6B+4C+2D)+(B-c-D) quating the coefticients, we et 8A + 4C+2D =0 -6A +8B - C - D=16 A- 6B +4C+2D =0 B-C- D 112 •:Solving, we gel 96, 85 B= c-D=-# A =- %3D
162%= z3(8A+4C+2D)+zY-6A+: +=(A-6B+4C+2D)+(B-c-D) quating the coefticients, we et 8A + 4C+2D =0 -6A +8B - C - D=16 A- 6B +4C+2D =0 B-C- D 112 •:Solving, we gel 96, 85 B= c-D=-# A =- %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:how to solve
equations
→ 162%= z°(8A+4c+2D)+zY-6A+8B-C-D)
+=(A-6B+4C+20)+(B-c-D)
Equating the coefficients, we aet
8A + 4C +2D =0
-6A +8B - C - D=16
A- 6B +4C+2D =0
B-C- D
=0
32
A=- 96
85
112
•:solving, we aet
%3D
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