162. 15.0 g of ice cubes at 0.0°C are combined with 150. g of liquid water at 70.0°C in a coffee cup calorimeter. Calculate the final temperature reached, assuming no heat loss or gain from the surroundings. (Data: specific heat capacity of H2O(1), c = 4.18 J/g.°C; H2O(s) A) 0.0 → H2O(1) B) 10.6 AH= 6.02 kJ/mol) C) 30.7 D) 43.2 E) 56.4
162. 15.0 g of ice cubes at 0.0°C are combined with 150. g of liquid water at 70.0°C in a coffee cup calorimeter. Calculate the final temperature reached, assuming no heat loss or gain from the surroundings. (Data: specific heat capacity of H2O(1), c = 4.18 J/g.°C; H2O(s) A) 0.0 → H2O(1) B) 10.6 AH= 6.02 kJ/mol) C) 30.7 D) 43.2 E) 56.4
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![162. 15.0 g of ice cubes at 0.0°C are combined with 150. g of liquid water at 70.0°C in a
coffee cup calorimeter. Calculate the final temperature reached, assuming no heat loss
or gain from the surroundings. (Data: specific heat capacity of H2O(1), c = 4.18 J/g.°C;
H2O(s)
A) 0.0
→ H2O(1)
B) 10.6
AH= 6.02 kJ/mol)
C) 30.7 D) 43.2 E) 56.4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F977a7d5b-612c-4a78-bbf9-0692c187c4ca%2F7e038190-94b1-4129-be3a-1f6f5ac84733%2Fr34er5.jpeg&w=3840&q=75)
Transcribed Image Text:162. 15.0 g of ice cubes at 0.0°C are combined with 150. g of liquid water at 70.0°C in a
coffee cup calorimeter. Calculate the final temperature reached, assuming no heat loss
or gain from the surroundings. (Data: specific heat capacity of H2O(1), c = 4.18 J/g.°C;
H2O(s)
A) 0.0
→ H2O(1)
B) 10.6
AH= 6.02 kJ/mol)
C) 30.7 D) 43.2 E) 56.4
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