*16-124. The disk rolls without slipping such that it has anangular acceleration of a = 4 rad/s and angular velocity ofw = 2 rad/s at the instant shown. Determine theacceleration of points A and B on the link and the link'sangular acceleration at this instant. Assume point A lies onthe periphery of the disk, 150 mm from C.w = 2 rad/sa = 4 rad/s500 mm150 mmB400 mm

To find the acceleration at point a (Note: The instantaneous center is at infinity ωAB=0rad/s)

Answered: *16-124. The disk rolls without…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Point A of the circular disk is at the angular position 0 = 0 at time t = 0. The disk has angular velocity wo = 0.26 rad/s at t = 0 and subsequently experiences an angular acceleration a = 3.0t where t is in seconds, and a is in radians per second squared. Determine the velocity and acceleration of point A in terms of fixed i and j unit vectors at time t = 1.1 s. Assume r = 185 mm. Answers: VA = 으아 aд = (i (i L. -X i + i i + i
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Part A At the instant 0 = 60°, link CD has an angular velocity wCD = 3 rad/s and an angular acceleration aCD = 2 rad/s?. The collar at C is pin connected to DC and slides over B as shown in (Figure 1). Determine the magnitude of the angular velocity of rod AB at this instant. Express your answer in radians per second to three significant figures. V ΑΣφ ? vec WAB = rad/s Submit Request Answer Figure Part B Determine the magnitude of the angular acceleration of rod AB at this instant. Express your answer in radians per second squared to three significant figures. 2 ft vec ? CD acD C AB = rad/s? 0 = 60 Submit Request Answer -2 ft
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position A of the circle disk is at angular position theta=0 and time t=0, disk have angular velocity w0= 1 rad/s when t=0. The angular acceleration of disk is a= 0.2sqrt(w) and a is rad/sec^2. Find vectors of the velocity and acceleration of position A when time = 1 s. Radius of disk r= 1.6 ft.
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