16.What is the work performed by a gas if it expands from 3.44 L to 6.19 L against a constant external pressure of 1.26 atm? Express the final answer in joules. (W=P x dV)
16.What is the work performed by a gas if it expands from 3.44 L to 6.19 L against a constant external pressure of 1.26 atm? Express the final answer in joules. (W=P x dV)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![16.What is the work performed by a gas if it expands from 3.44 L to 6.19 L against a
constant external pressure of 1.26 atm? Express the final answer in joules. (W=P x dV)
17.Calculate the heat involved when 25.0 g of Fe increase temperature from 22° C to 76°C.
The specific heat of Fe is 0.449 J/g• °c. (Q = ms(t2-t¡)
18.Nitrogen gas reacts with oxygen gas to make NO(g) while absorbing 180 W. Is this
process exothermic or endothermic?
19.Given the thermochemical equation: N2(g) + 3H2(g) + 2NH3(g) AH =-91.8kJ
How much heat is given off when 1.00 g ofH2 reacts?
20.What is the work when 2,345 mL of gas contract to 887 ml- under an external pressure of
348 torr? (1 mmHg = 1 torr) (W = P x dV)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F458a99a5-96de-4182-aeaf-c00416d43e3b%2F54bc36f0-afc2-43f5-99f7-8b40aa4299b8%2F4lph14_processed.jpeg&w=3840&q=75)
Transcribed Image Text:16.What is the work performed by a gas if it expands from 3.44 L to 6.19 L against a
constant external pressure of 1.26 atm? Express the final answer in joules. (W=P x dV)
17.Calculate the heat involved when 25.0 g of Fe increase temperature from 22° C to 76°C.
The specific heat of Fe is 0.449 J/g• °c. (Q = ms(t2-t¡)
18.Nitrogen gas reacts with oxygen gas to make NO(g) while absorbing 180 W. Is this
process exothermic or endothermic?
19.Given the thermochemical equation: N2(g) + 3H2(g) + 2NH3(g) AH =-91.8kJ
How much heat is given off when 1.00 g ofH2 reacts?
20.What is the work when 2,345 mL of gas contract to 887 ml- under an external pressure of
348 torr? (1 mmHg = 1 torr) (W = P x dV)
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V1 = 3.44 L , V2 = 6.19 L
P = 1.26 atm
dV = V2 - V1 = 6.19 - 3.44 =2.75 L
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