16.4%. E76.9% =30.3/- 1. When three forces are in equilibrium, the resultant of any two forces should be equal in magnitude to the third force and opposite in direction. If you did not find this to be true, calculate your % error. This is done by subtracting the magnitudes of the resultant force and the third force, dividing the difference by the magnitude of the third force, and then multiplying the product by 100. 2. Predict what would happen to the reading on the third scale if the first two scales were to be moved closer together and the strings adjusted so they would indicate the same forces as before.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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please help with questions 1,2, and 3 based on the data
remaining force vector in each case.
Data Table - Graphic force - Distance Scale (1 cm =
_newton)
Trial 1
Trial 2
Trial 3
Trial 4
Scale F 1
1,8 N
1.1N.
1.11N
N)
Scale F 2
(N)
Angle
1.27N
1.2N
1.4 N
63°
52°
53°
Resultant F (R)
(N)
Seale F 3
(N)
Percent
Measured>
4
1.525 N
2.3 N
2.475 N
Accepted>
1.31N
1.3N
1.9 N
6.
Error
16.4%
11.31-1.525)
76.9%
30.3%
1.9-2.4751
1.9
Queştions:
11.3-2.31 x 100
XT00
X 100
1.31
ニ16.4/0.
1.3
ニコ6.92
= 30.3%
1. When three forces are in equilibrium, the resultant of any two forces should be equal
in magnitude to the third force and opposite in direction. If you did not find this to be
true, calculate your % error. This is done by subtracting the magnitudes of the resultant
force and the third force, dividing the difference by the magnitude of the third force, and
then multiplying the product by 100.
2. Predict what would happen to the reading on the third scale if the first two scales were
to be moved closer together and the strings adjusted so they would indicate the same
forces as before.
3. If each of the three scrales is applying a force in a different direction, why is it
irmpossible for the angle between any two of the forces to be 180°?
Transcribed Image Text:remaining force vector in each case. Data Table - Graphic force - Distance Scale (1 cm = _newton) Trial 1 Trial 2 Trial 3 Trial 4 Scale F 1 1,8 N 1.1N. 1.11N N) Scale F 2 (N) Angle 1.27N 1.2N 1.4 N 63° 52° 53° Resultant F (R) (N) Seale F 3 (N) Percent Measured> 4 1.525 N 2.3 N 2.475 N Accepted> 1.31N 1.3N 1.9 N 6. Error 16.4% 11.31-1.525) 76.9% 30.3% 1.9-2.4751 1.9 Queştions: 11.3-2.31 x 100 XT00 X 100 1.31 ニ16.4/0. 1.3 ニコ6.92 = 30.3% 1. When three forces are in equilibrium, the resultant of any two forces should be equal in magnitude to the third force and opposite in direction. If you did not find this to be true, calculate your % error. This is done by subtracting the magnitudes of the resultant force and the third force, dividing the difference by the magnitude of the third force, and then multiplying the product by 100. 2. Predict what would happen to the reading on the third scale if the first two scales were to be moved closer together and the strings adjusted so they would indicate the same forces as before. 3. If each of the three scrales is applying a force in a different direction, why is it irmpossible for the angle between any two of the forces to be 180°?
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