16 V 1. Calculate the Thevenin Equivalent circuit (use conversion from Thevenin to Norton and vice versa in order to simplify the circuit) 2. Show that doesn't matter what value choose for Load resister at ab terminal, the Thevenin equivalent circuit will always be the same + 4A 302 ww 40. 502 12 Ω 802 602 w w w 602 202 + 24 V 18 V ob

For the circuit shown in number 6, find the equivalent current source and also the load current.

i want the discussion for this circuit

For the circuit shown below: Bpc = 100, VBe = 0.7V, V† = 26 mV. 1. What are the 5 steps? 2. What is the purpose of C1 and C3? 3. What is the purpose of C2? +12 V Re 22 kl 2N3904 RE 560 1 6.8 kfl

VDD Rp Cc Q2 Cc RL RG Rs For the series-connected identical JFETS of Figure above, IDSS = 8 mA and VP = 4 V, VDD = 15 V, RS = 2 kQ, RD = 5 k2, and RG = 1 ΜΩ, then: * -- V. 1. The value of Vpsoi is 2. The value of Ipoı is is mA. -- V. 3. The value of VGSQ1 4. The value of Vcso2 is 5. The value of VDSQ2 is V. -- V. --

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Employing the characteristic curve in Figure 1 and obtain the design for a voltage divider configuration that has a Q point of ICQ = 5 mA and VCEQ = 8 V. Using VCC = 24 V and RC = 3RE. Find the following: a) Draw the configuration indicating each of the elements b) Determine RC and RE c) Find VE d) Determine VB e) Calculate ? for point Q f) Find R2 if R1 = 24 kΩ

Draw the simplified circuits properly and show all the steps

Determine the approximate value of VGG of Figure 52. VDD T15V 1.5kQ Q1 V, = 9.5V 1MQ = 8mA DS V =- 4.5V EVGG Figure 52. 1.453 V -1.2 V -7.547 V O -3.281 V