Given: VCC VCC = 22V R1 = 2.2 kOhm R2 = 82 kOhm R3 = 16 kOhm R4 = 0.75 kOhm R2 R1 RL = 2.7 kOhm Beta = 220 Со Vi Ci HH Vo VEB = 0.68 V Ci = Co = Ce = 2 uF Solve for: R33 R4 Се A. ETH, RTH B. IB, IE c. VC, VE ww ww ww ww

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question

-SHOW YOUR COMPLETE SOLUTION

-SHOW  THE KVL  LOOP EQUATIONS

-SHOW CORRECT CIRCUIT DIAGRAMS

-USE EXACT ANALYSIS (DO NOT USE APPROXIMATION)

-USE 2 DECIMAL PLACES

Given:
VCC
VCC = 22V
R1 = 2.2 kOhm
R2 = 82 kOhm
R3 = 16 kOhm
R4 = 0.75 kOhm
R2
R1
RL = 2.7 kOhm
Beta = 220
Со
Ci
Vo
VEB = 0.68 V
Vi
Ci = Co = Ce = 2 uF
Solve for:
R33
R4
Ce
A. ETH, RTH
В. ТВ, IЕ
c. VC, VE
ww
ww
ww
ww
Transcribed Image Text:Given: VCC VCC = 22V R1 = 2.2 kOhm R2 = 82 kOhm R3 = 16 kOhm R4 = 0.75 kOhm R2 R1 RL = 2.7 kOhm Beta = 220 Со Ci Vo VEB = 0.68 V Vi Ci = Co = Ce = 2 uF Solve for: R33 R4 Ce A. ETH, RTH В. ТВ, IЕ c. VC, VE ww ww ww ww
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