*16 O The box-like Gaussian surface shown in Fig. 23-38 en- closes a net charge of +24.0eo C and lies in an electric field given by E = [(10.0 + 2.00x)i – 3.00j + bzk] N/C, with x and z in me- ters and b a constant. The bottom face is in the xz plane; the top face is in the horizontal plane passing through y, = 1.00 m. For x = 1.00 m,x2 = 4.00 m, z1 = 1.00 m, and z2 = 3.00 m, what is b? -- Figure 23-38 Problem 16.

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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*16 O The box-like Gaussian surface shown in Fig. 23-38 en-
closes a net charge of +24.0eo C and lies in an electric field given
by E = [(10.0 + 2.00x)i – 3.00j + bzk] N/C, with x and z in me-
ters and b a constant. The bottom face is in the xz plane; the top face
is in the horizontal plane passing through y, = 1.00 m. For x =
1.00 m,x2 = 4.00 m, z1 = 1.00 m, and z2 = 3.00 m, what is b?
--
Figure 23-38 Problem 16.
Transcribed Image Text:*16 O The box-like Gaussian surface shown in Fig. 23-38 en- closes a net charge of +24.0eo C and lies in an electric field given by E = [(10.0 + 2.00x)i – 3.00j + bzk] N/C, with x and z in me- ters and b a constant. The bottom face is in the xz plane; the top face is in the horizontal plane passing through y, = 1.00 m. For x = 1.00 m,x2 = 4.00 m, z1 = 1.00 m, and z2 = 3.00 m, what is b? -- Figure 23-38 Problem 16.
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