Locate the centroid of the shaded area shown. Draw the figure with the centroid. (KINDLY FOLLOW THE SAMPLE SOLUTION PROVIDED) 16 cm8 cm8 cm8 cm-X 2. Locate the centroid of the shaded area shown.Divide the area into regular geometric shapes. Makesure the centroids of the geometric shapes can beidentified.12"a, in².(1/2)(12)(6)=36(12)(6)=72-(1/2)(12)(6)=-36A=72PartTotalΣαχ360Ax = 5"9=Eay=4722ỹ= 6"x, in46612"The area can be divided into three partsas shown, with the unshaded triangle asa negative area since it is not part of theshaded area.y, inax, in³8(36)(4)=1443(72)(6)=432ay, in³(36) (8)=288(72)(3)=216(-36) (2)=-724322(-36) (6)=-216360

Answered: Image /qna-images/answer/a5f999b8-be0f-4868-95f6-14ab4d1bb314.jpg

Answered: 16 cm 8 cm 8 cm 8 cm -X

Engineering

Civil Engineering

16 cm 8 cm 8 cm 8 cm -X

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Methods of Surveying

Surveying is the practice to determine the relative three-dimensional positions of various points on the earth’s surface. This is done by computing the vertical and horizontal distances, angles between the points, collecting the observations, and plotting them on a map of any appropriate scale. Accuracy can be achieved by using the latest instruments like a theodolite, tachometer, etc. Leveling is a subdivision of surveying where the objective is to locate the elevation of objects considering a datum level.

Question

Locate the centroid of the shaded area shown. Draw the figure with the centroid. (KINDLY FOLLOW THE SAMPLE SOLUTION PROVIDED)

2. Locate the centroid of the shaded area shown.
Divide the area into regular geometric shapes. Make
sure the centroids of the geometric shapes can be
identified.
12"
a, in².
(1/2)(12)(6)=36
(12)(6)=72
-(1/2)(12)(6)=-36
A=72
Part
Total
Σαχ
360
A
x = 5"
9=Eay=4722
ỹ= 6"
x, in
4
6
6
12"
The area can be divided into three parts
as shown, with the unshaded triangle as
a negative area since it is not part of the
shaded area.
y, in
ax, in³
8
(36)(4)=144
3
(72)(6)=432
ay, in³
(36) (8)=288
(72)(3)=216
(-36) (2)=-72
432
2
(-36) (6)=-216
360

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