= 16 a Problem #3: Find the surface area of the part of the paraboloid z = 64 - x² - y² that is within the cylinder x² + y² above the first quadrant. Problem #3: pi*(65^(3/2)-1)/24 - 1) (653/2 24 Just Save Your work has been saved! (Back to Admin Page). Problem #3 Attempt #1 Your Answer: 653/2-1 0/3x Your Mark: Enter your answer symbolically, as in these examples 24 Attempt #2 Attempt #3 653/2 J 12 2 0/3x Submit Problem #3 for Grading

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