Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Text Transcription for Educational Website:**
---
8. **Calculate the frequency of light that has a wavelength of 4.25 x 10^-9 m. Identify the type of electromagnetic radiation.**
\[
v = c / \lambda
\]
\[
v = 3.0 \times 10^8 \, \text{m/s} / 4.25 \times 10^{-9} \, \text{m}
\]
\[
v = 7.1 \times 10^{16} \, \text{Hz}
\]
**UV Radiation**
9. **What wavelength (λ) of radiation has photons of energy (E) at 2.87 x 10^-16 J?**
10. **A photon of visible light has a frequency (ν) of 4.3 x 10^14 s^-1. What is the energy (E) of this photon?**
11. **Calculate the energy (E) of a photon of radiation whose wavelength (λ) is 322 nm.**
**Note:** \(1 \, \text{nm} = 1 \times 10^{-9} \, \text{m}\)
12. **What wavelength (λ) of radiation has photons of energy (E) at 2.87 x 10^-16 J?**
---
**Explanation of Concepts:**
- **Frequency (ν) and Wavelength (λ):** In electromagnetic radiation, the speed of light (c) is constant and equal to approximately \(3.0 \times 10^8 \, \text{m/s}\). The relationship between frequency, wavelength, and the speed of light is given by the equation \(v = c / \lambda\).
- **Energy of Photons (E):** The energy of a photon can be calculated using the frequency by \(E = h \cdot v\), where \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)).
- **Electromagnetic Spectrum:** The type of electromagnetic radiation can be identified based on the frequency or wavelength. For instance, ultraviolet (UV) radiation has frequencies typically ranging from \(10^{15}\) to \(10^{17} \, \text{Hz}\).
Please ensure students understand how to apply these formulas](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F58ca8a72-4839-4138-9af6-242170ab3eb7%2F64f92463-b2c8-41bb-821d-99aabb1f9bfd%2Fiju5ice_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Text Transcription for Educational Website:**
---
8. **Calculate the frequency of light that has a wavelength of 4.25 x 10^-9 m. Identify the type of electromagnetic radiation.**
\[
v = c / \lambda
\]
\[
v = 3.0 \times 10^8 \, \text{m/s} / 4.25 \times 10^{-9} \, \text{m}
\]
\[
v = 7.1 \times 10^{16} \, \text{Hz}
\]
**UV Radiation**
9. **What wavelength (λ) of radiation has photons of energy (E) at 2.87 x 10^-16 J?**
10. **A photon of visible light has a frequency (ν) of 4.3 x 10^14 s^-1. What is the energy (E) of this photon?**
11. **Calculate the energy (E) of a photon of radiation whose wavelength (λ) is 322 nm.**
**Note:** \(1 \, \text{nm} = 1 \times 10^{-9} \, \text{m}\)
12. **What wavelength (λ) of radiation has photons of energy (E) at 2.87 x 10^-16 J?**
---
**Explanation of Concepts:**
- **Frequency (ν) and Wavelength (λ):** In electromagnetic radiation, the speed of light (c) is constant and equal to approximately \(3.0 \times 10^8 \, \text{m/s}\). The relationship between frequency, wavelength, and the speed of light is given by the equation \(v = c / \lambda\).
- **Energy of Photons (E):** The energy of a photon can be calculated using the frequency by \(E = h \cdot v\), where \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js}\)).
- **Electromagnetic Spectrum:** The type of electromagnetic radiation can be identified based on the frequency or wavelength. For instance, ultraviolet (UV) radiation has frequencies typically ranging from \(10^{15}\) to \(10^{17} \, \text{Hz}\).
Please ensure students understand how to apply these formulas
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