15. How much heat is required to convert 135 g of ice at -15 °C into water vapor at 120 °C? (Assume c of steam = 1.996 J/g-°C, c of water = 4.1858 J/g-°C, c of ice =2.090 J/g-"C. Lv of water = 540 cal/g & Lf of water = 80 cal/g)
15. How much heat is required to convert 135 g of ice at -15 °C into water vapor at 120 °C? (Assume c of steam = 1.996 J/g-°C, c of water = 4.1858 J/g-°C, c of ice =2.090 J/g-"C. Lv of water = 540 cal/g & Lf of water = 80 cal/g)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Answer no. 15 only
![Temperature & Heat
13 At 30 °C the volume of an aluminum sphere is 30 cm³. The coefficient of linear
expansion is 24 x 10 C¹. If the final volume is 29.5cm, what is the final temperature of
the aluminum sphere
-3a
14. A 500-gram cube read is heated from 25 °C to 75 °C. How much energy was required
to the lead? The specific heat of lead is 0.129-1/a-C.
15. How much heat is required to convert 135 g of ice at -15 °C into water vapor at 120 °C?
(Assume c of steam = 1.996 J/g-°C, c of water = 4.1858 J/g-°C, c of ice =2.090 J/g-"C,
Lv of water = 540 cal/g & Lf of water = 80 cal/g)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc129a3c7-0b6d-43f7-b060-44204c55022b%2Fe8cc4263-d238-40f4-95f1-b6931cebc417%2Fdc615qe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Temperature & Heat
13 At 30 °C the volume of an aluminum sphere is 30 cm³. The coefficient of linear
expansion is 24 x 10 C¹. If the final volume is 29.5cm, what is the final temperature of
the aluminum sphere
-3a
14. A 500-gram cube read is heated from 25 °C to 75 °C. How much energy was required
to the lead? The specific heat of lead is 0.129-1/a-C.
15. How much heat is required to convert 135 g of ice at -15 °C into water vapor at 120 °C?
(Assume c of steam = 1.996 J/g-°C, c of water = 4.1858 J/g-°C, c of ice =2.090 J/g-"C,
Lv of water = 540 cal/g & Lf of water = 80 cal/g)
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