15.16.In a saturated solution of lead (II) chloride, the concentration of chloride ion is6.2 x 104 mol/L. The Ksp of lead(II) chloride would be which of the following?17.a. 1.9 x 107b. 6.0 x 10-¹1c. 1.2 x 10-10The following diagram represents a kinetic energy distribution at two temperatures.d. 2.3 x 10-¹7e. none of the aboveNumber of Molecules with aParticular Kinetic Energya. T₁ > T₂b. T₂ > T₁C. T₁ T₂Kinetic EnergyIn comparing the two temperatures, it is obvious thatI ₂d. T₁ = T₂e. cannot be determinedA full syringe contains this equilibrium:2 NO₂(g)=N₂O4(g)colourless gasbrown gasBased on Le Chatelier's principle, what would be observed when the syringe is usedto compress this gas mixture?a. the mixture gets darkerb. the mixture gets darker thenlighterc. the mixture get lighter then darkerd. the mixture gets lightere. none of the above

Ans 1. PbCl2 (s) ⇌ Pb2+(aq) + 2Cl- (aq)...........(i) Ksp is given as Ksp = [Pb2+][Cl−]2 According…

15. 16. In a saturated solution of lead(II) chloride, the concentration of chloride ion is 6.2 x 104 mol/L. The Ksp of lead (II) chloride would be which of the following? a. 1.9 x 10-7 b. 6.0 x 10-¹1 c. 1.2 x 10-10 d. 2.3 x 10-¹7 e. none of the above The following diagram represents a kinetic energy distribution at two temperatures. of Molecules with a ar Kinetic Energy T

15. 16. In a saturated solution of lead(II) chloride, the concentration of chloride ion is 6.2 x 104 mol/L. The Ksp of lead (II) chloride would be which of the following? a. 1.9 x 10-7 b. 6.0 x 10-¹1 c. 1.2 x 10-10 d. 2.3 x 10-¹7 e. none of the above The following diagram represents a kinetic energy distribution at two temperatures. of Molecules with a ar Kinetic Energy T

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Was wondering how to solve this hw problem? Calcium Flouride (dissociation) K@25 C = 3.94 *10^-11 Calcium fluoride is not very soluble in water. ** Its dissociation is: CaF2 (s) Ca²+ (aq) + 2 F¯ (aq) a. At 25°C, how many milligrams of CaF2 would dissolve in 2.0 L of water? b. What were your initial and final values of Q?
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Suppose 234.3 mg of PbCl2 was added to 16.0 mL of water in a flask, and the solution was allowed to reach equilibrium at 21.0 oC. Some solute remained at the bottom of the flask after equilibrium, and the solution was filtered to collect the remaining PbCl2, which had a mass of 91.6 mg . What is the solubility of PbCl2 (in g/L)? -Express the concentration in grams per liter to three significant figures.
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