[15] (4) GIVEN: a > 0, a constant, and the directed path C, (Add extra pages, as needed. from A = (a,0) to B= (0, a), directed along the line segment, AB; and, the vector field in the xy - plane, F = (x² - y², x² + y²). FIND: The path integral: F•ds (0, a) / 1 1 ΚΑ (a,0) / X 1 1 1 F = (x² − y², x² + y²)

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Chapter2: Second-order Linear Odes
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for the first image attach please do the calculations similar to the second image attach

please please answer every correctly also this is not a graded question I would really appreciate if you would answer

[15] (4) GIVEN: a > 0, a constant, and the
directed path C,
from A = (a,0) to B= (0, a),
directed along the line segment, AB;
Add extra
pages, as
needed.
and, the vector field in the xy - plane,
(x² − y², x² + y²).
F
FIND: The path integral: F•ds
=
6 77
1
A
(a,0) /
1
17
F = (x² − y², x² + y²)
1
1
1
A 1
1
X
Transcribed Image Text:[15] (4) GIVEN: a > 0, a constant, and the directed path C, from A = (a,0) to B= (0, a), directed along the line segment, AB; Add extra pages, as needed. and, the vector field in the xy - plane, (x² − y², x² + y²). F FIND: The path integral: F•ds = 6 77 1 A (a,0) / 1 17 F = (x² − y², x² + y²) 1 1 1 A 1 1 X
[15] (4)
GIVEN: a > 0, a constant, and the
directed path c,
from A = (a,0) to B= (a, a) to C = (0,0),
directed along the line segments, AB, BC;
and, the vector field in the xy - plane,
F = (x + y, - x).
FIND: The path integral: F·ds
METHOD:
1
AB: C = (a,y), ye [o,a]
BC: -C₂ = (x,x), z€ [0,a]
di
F•
=
Lên đã đến đâện đã
-C₂
.
Lên đã = f(a+y, a)(0,1)
= √² (-a) dy = − a²
Hence,
(a,0)
F = (x+y₁-x)
·a
d
√ F• dî = [ª (2x,-z). (1,1) 4 = √x+
-C₂
= 1/α²
√ F• dª = -a² - £a² = −2a²
The negative
value of the answer,
(checks with the sketch.
Transcribed Image Text:[15] (4) GIVEN: a > 0, a constant, and the directed path c, from A = (a,0) to B= (a, a) to C = (0,0), directed along the line segments, AB, BC; and, the vector field in the xy - plane, F = (x + y, - x). FIND: The path integral: F·ds METHOD: 1 AB: C = (a,y), ye [o,a] BC: -C₂ = (x,x), z€ [0,a] di F• = Lên đã đến đâện đã -C₂ . Lên đã = f(a+y, a)(0,1) = √² (-a) dy = − a² Hence, (a,0) F = (x+y₁-x) ·a d √ F• dî = [ª (2x,-z). (1,1) 4 = √x+ -C₂ = 1/α² √ F• dª = -a² - £a² = −2a² The negative value of the answer, (checks with the sketch.
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