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Q: 4 If f(x) = 4 + + find f'(x). | x2 Preview Find f'(3). Preview

A: Given that the function   f(x) = 4+5x+4x2 To find f'(x) and f'(3)

Q: ƒ' (4) = If f(x) = 3√√√x(x³ − 2√x + 2), find f'(4).

A: Given that

Q: Let f(x)=4x^(3)- 8 Find f '(4)

A:

Q: 1 4 √x 5 18 dx =

A:

Q: If f(x) = 6(a-3/+7), find f'(2). Find f'(5).

A:

Q: Find f. f'(x)  = x-1/3    ,f(1)  =1, f(-1)  = -1

A: To find f(x) we integrate f'(x) C=integrating constant

Q: f6) =V20x (?,) f'G) f'(x)

A:

Q: Identify the open interval(s) where f is concave up. [A] (-∞, -1) [B] (-∞, -3) U (-1,2) [C] (-1,00)…

A: for concave up , f'(x) is increasing For given graph , f'(x) is increasing on

Q: Find f'(x) if f(x) = 1 (x+csda4+10))³

A: *concept:- cscx = 1/sinx. d/dx (sinx) = cosx. d/dx (x^{n}) = nx^{(n-1)}

Q: find f'la) f(x)%3D(X

A: The given function is: f(x)=x-1x2

Q: F=11+/2x+3, find F'(3) find F'(8)

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Q: F’(-4)=

A:

Q: (x) = 5x(2x* _ _5 f'(x) = help (formulas) Given f(x) = 5x 6), find ƒ'(x). x+6)

A:

Q: Find f. f ''(x) = x−2,    x > 0,    f(1) = 0,    f(7) = 0

A: I am going to solve the given problem by using some simple calculus to get the reqiuired result.

Q: Find f. f ''(t) = 9/sqt t,    f(4) = 29,    f '(4) = 9

A:

Q: Let f(x) - 6e* +2 + e'. f'(0) =

A: The given function is f(x)=-6ex+2+e1

Q: Find f. f"(x) = 1 - 6x + 48x², f(0) = 1, f'(0) = 2 1.

A:

Q: 3s+7, Find L'f 's2+9*

A:

Q: If f(x) = (5x + 4)-1, find f'(x). %3D Find f'(5). Get help: Video

A:

Q: Evaluate the integral. 4 1 dx 2x Ji

A:

Q: If f(x) = 3/7(2 – 7a + 5), find f'(x). - Find f'(3).

A: Given:- f(x) = 3√x(x3-7√x+5)  To find:- f'(x) and f'(3)

Q: Find  f'(a)

A: Here given function as ft=2t+1t+3

Q: If f(x) = (5x +6) find f'(x). Find f'(3).

A: topic - derivative of a function