14.53 • A 1.80-kg connecting rod from a car engine is pivoted about a horizontal knife edge as shown in Fig. E14.53. The center of gravity of the rod was located by balancing and is 0.200 m from the pivot. When the rod is set into small-amplitude oscilla- tion, it makes 100 complete swings in 120 s. Calculate the moment of inertia of the rod about the rotation axis through the pivot. Figure E14.53 d = 0.200 m

Classical Dynamics of Particles and Systems
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ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter3: Oscillations
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• A 1.80-kg connecting Figure E14.53
rod from a car engine is pivoted
about a horizontal knife edge as
shown in Fig. E14.53. The center
of gravity of the rod was located
by balancing and is 0.200 m
from the pivot. When the rod is
set into small-amplitude oscilla-
tion, it makes 100 complete
swings in 120 s. Calculate the
14.53
d = 0.200 m
cg
moment of inertia of the rod
about the rotation axis through
the pivot.
Transcribed Image Text:• A 1.80-kg connecting Figure E14.53 rod from a car engine is pivoted about a horizontal knife edge as shown in Fig. E14.53. The center of gravity of the rod was located by balancing and is 0.200 m from the pivot. When the rod is set into small-amplitude oscilla- tion, it makes 100 complete swings in 120 s. Calculate the 14.53 d = 0.200 m cg moment of inertia of the rod about the rotation axis through the pivot.
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