14.2. To calculate the number of л bonds and rings in a molecule-collectively called the “sites of unsaturation" apply the formula given below: - n = number of C atoms (2n+2)-m-p+q m = number of H atoms No. of sites of unsaturation = p = number of halogen atoms 2 q = number of N atoms For the molecule under consideration, C6H13 NO2 n = 6 m = 13 9 = 1 No. of sites of unsaturation = 2(6)+213 +1 2 = 0 sites of unsaturation This molecule has no rings or л bonds.

Chemistry: The Molecular Science
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Chapter7: Molecular Structures
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why are there 0 sites of unsaturation? wouldnt there be 1?

14.2. To calculate the number of л bonds and rings in a molecule-collectively called the “sites of
unsaturation" apply the formula given below:
-
n = number of C atoms
(2n+2)-m-p+q
m = number of H atoms
No. of sites of unsaturation =
p = number of halogen atoms
2
q = number of N atoms
For the molecule under consideration,
C6H13 NO2
n = 6
m = 13
9 = 1
No. of sites of unsaturation =
2(6)+213 +1
2
= 0 sites of unsaturation
This molecule has no rings or л bonds.
Transcribed Image Text:14.2. To calculate the number of л bonds and rings in a molecule-collectively called the “sites of unsaturation" apply the formula given below: - n = number of C atoms (2n+2)-m-p+q m = number of H atoms No. of sites of unsaturation = p = number of halogen atoms 2 q = number of N atoms For the molecule under consideration, C6H13 NO2 n = 6 m = 13 9 = 1 No. of sites of unsaturation = 2(6)+213 +1 2 = 0 sites of unsaturation This molecule has no rings or л bonds.
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