14. (II) (a) A long jumper leaves the ground at 45° above the horizontal and lands 8.0 m away. What is her “takeoff" speed vo ? (b) Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 m away horizontally and 2.5 m, vertically below. If she long jumps from the edge of the left bank at 45° with the speed calculated in (a), how long, or short, of the opposite bank will she land (Fig. 3–43)? a) o. co = 8.9"/s %3D b) Ax = 10.0m 45° 2.5 m 10.0 m

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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44. (II) (a) A long jumper leaves the ground at 45° above the
horizontal and lands 8.0 m away. What is her “takeoff"
speed vo? (b) Now she is out on a hike and comes to the left
bank of a river. There is no bridge and the right bank is
10.0 m away horizontally and 2.5 m, vertically below. If she
long jumps from the edge of the left bank at 45° with the
speed calculated in (a), how long, or short, of the opposite
bank will she land (Fig. 3–43)?
a) v, =8.9-/s
b) Ax = 10.0m
45°
2.5 m
10.0 m
Transcribed Image Text:44. (II) (a) A long jumper leaves the ground at 45° above the horizontal and lands 8.0 m away. What is her “takeoff" speed vo? (b) Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 m away horizontally and 2.5 m, vertically below. If she long jumps from the edge of the left bank at 45° with the speed calculated in (a), how long, or short, of the opposite bank will she land (Fig. 3–43)? a) v, =8.9-/s b) Ax = 10.0m 45° 2.5 m 10.0 m
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