14. A pin-connected structure consists of a rigid beam ABCD and two supporting bars. Bar (1) is an aluminum alloy [E = 70 GPa] with a cross-sectional area of A₁ = 2,400 mm². Bar (2) is a bronze alloy [E = 100 GPa] with a cross-sectional area of A2 = 6,000 mm². All bars are unstressed before the load P is applied. If a load of P = 535 kN is applied at B, determine the normal force in bar (1).
14. A pin-connected structure consists of a rigid beam ABCD and two supporting bars. Bar (1) is an aluminum alloy [E = 70 GPa] with a cross-sectional area of A₁ = 2,400 mm². Bar (2) is a bronze alloy [E = 100 GPa] with a cross-sectional area of A2 = 6,000 mm². All bars are unstressed before the load P is applied. If a load of P = 535 kN is applied at B, determine the normal force in bar (1).
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![14. A pin-connected structure consists of a rigid beam ABCD and two supporting bars. Bar
(1) is an aluminum alloy [E = 70 GPa] with a cross-sectional area of A₁ = 2,400 mm².
Bar (2) is a bronze alloy [E = 100 GPa] with a cross-sectional area of A2 = 6,000 mm².
All bars are unstressed before the load P is applied. If a load of P = 535 kN is applied at
B, determine the normal force in bar (1).
A)
B)
D)
E)
2.9 m
0.8 m
391 kN
325 kN
301 kN
247 kN
181 kN
B
1.5 m
P = 535 KN
(2)
C
3.3 m
1.2 m
F₁
K
0.8m
D
+
535
1.2m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff1f0c905-f4f0-401f-9e11-7e89b9e303f0%2F82df424c-2121-4f47-96d4-aaa488e40ab2%2Fq7ii6l2_processed.png&w=3840&q=75)
Transcribed Image Text:14. A pin-connected structure consists of a rigid beam ABCD and two supporting bars. Bar
(1) is an aluminum alloy [E = 70 GPa] with a cross-sectional area of A₁ = 2,400 mm².
Bar (2) is a bronze alloy [E = 100 GPa] with a cross-sectional area of A2 = 6,000 mm².
All bars are unstressed before the load P is applied. If a load of P = 535 kN is applied at
B, determine the normal force in bar (1).
A)
B)
D)
E)
2.9 m
0.8 m
391 kN
325 kN
301 kN
247 kN
181 kN
B
1.5 m
P = 535 KN
(2)
C
3.3 m
1.2 m
F₁
K
0.8m
D
+
535
1.2m
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