[14] How many liters of the antifreeze ethylene glycol (HOCH₂CH₂OH, 54.09 g/mol) would you add to a car-radiator containing 6.50 L of water to keep it from freezing if the coldest winter temperature in your area is -20°C? Calculate the boiling point of this water-ethylene glycol mixture. (The density of ethylene glycol is 1.11 g/mL, the molal freezing and boiling point constants are respectively kf = 1.86°/m and kb= 0.52°/m).

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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[14] How many liters of the antifreeze ethylene glycol (HOCH₂CH₂OH, 54.09 g/mol) would you add to a car-radiator containing
6.50 L of water to keep it from freezing if the coldest winter temperature in your area is -20°C? Calculate the boiling point of this
water-ethylene glycol mixture. (The density of ethylene glycol is 1.11 g/mL, the molal freezing and boiling point constants are
respectively kf = 1.86°/m and kb= 0.52 °/m).
&
Page
5
Transcribed Image Text:4- 30- [14] How many liters of the antifreeze ethylene glycol (HOCH₂CH₂OH, 54.09 g/mol) would you add to a car-radiator containing 6.50 L of water to keep it from freezing if the coldest winter temperature in your area is -20°C? Calculate the boiling point of this water-ethylene glycol mixture. (The density of ethylene glycol is 1.11 g/mL, the molal freezing and boiling point constants are respectively kf = 1.86°/m and kb= 0.52 °/m). & Page 5
Expert Solution
Step 1: Freezing point depression

Freezing point depression refers to the lowering of the freezing point of solvents upon the addition of solutes. 

Boiling point elevation refers to the increase in the boiling point of a solvent upon the addition of a solute

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