14) For the reaction, A + 2B → C + 2D, the following data were obtained [A] (mol L-1) [B] (mol L-1) Rate (mol L-1 s-1) 0.100 0.200 0.000360 0.200 0.200 0.000720 0.100 0.400 0.000720 Experiment 1 23 A) the rate law is therefore: rate = k[A] B) the rate law is therefore: rate = k[A]²[B] C) the rate law is therefore: rate = k[B] D) the rate law is therefore: rate = k[A][B]² E) the rate law is therefore: rate = k[A][B]
14) For the reaction, A + 2B → C + 2D, the following data were obtained [A] (mol L-1) [B] (mol L-1) Rate (mol L-1 s-1) 0.100 0.200 0.000360 0.200 0.200 0.000720 0.100 0.400 0.000720 Experiment 1 23 A) the rate law is therefore: rate = k[A] B) the rate law is therefore: rate = k[A]²[B] C) the rate law is therefore: rate = k[B] D) the rate law is therefore: rate = k[A][B]² E) the rate law is therefore: rate = k[A][B]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![14) For the reaction, A + 2B → C + 2D, the following data were obtained.
Experiment
1
[A] (mol L-¹)
0.100
[B] (mol L-1) Rate (mol L-1 s-1)
0.200
0.000360
0.200
0.200
0.000720
0.100
0.400
0.000720
23
A) the rate law is therefore: rate = k[A]
B) the rate law is therefore: rate = k[A]²[B]
C) the rate law is therefore: rate = k[B]
D) the rate law is therefore: rate = k[A][B]²
E) the rate law is therefore: rate = k[A][B]
14)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2e1cb03f-91d2-4991-91c8-37c8965f1bd7%2F840dedea-d049-424f-aae3-e0e801c83c13%2F5vt7xe4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:14) For the reaction, A + 2B → C + 2D, the following data were obtained.
Experiment
1
[A] (mol L-¹)
0.100
[B] (mol L-1) Rate (mol L-1 s-1)
0.200
0.000360
0.200
0.200
0.000720
0.100
0.400
0.000720
23
A) the rate law is therefore: rate = k[A]
B) the rate law is therefore: rate = k[A]²[B]
C) the rate law is therefore: rate = k[B]
D) the rate law is therefore: rate = k[A][B]²
E) the rate law is therefore: rate = k[A][B]
14)
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