14-12. (a) Comment on the following: For a binomial distribution, mean = 7 and variance = (b) A binomial variable on 100 trials has 6 as its standard deviation. 1his statement is : (i) valid, (ii) invalid (iii) cannot say. Choose the correct alternative.
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- Suppose that an accounting firm does a study to determine the time needed to complete one person's tax forms. It randomly surveys 200 people. The sample mean is 22.3 hours. There is a known population standard deviation of 7.0 hours. The population distribution is assumed to be normal. Find the following. (Enter exact numbers as integers, fractions, or decimals.) (i) x = (ii) ? = (iii) n =3. Is it possible to obtain a negative value for thevariance or the standard deviation?4. A distribution of scores has = 70. The z-score for X = 65 is computed and a value of z = +1.00. Regardless of the value of the standard deviation, why must this z-score be incorrect?
- suppose that a random sample of size 20 is taken from a normal distribution with unknown mean and known variance is equal to 1 and me is found to be 10 and normal distribution was used to as a prayer for the mean and it was found that the posterior maine was 15 and posterior standard aviation was 0.1 what is the mean and standard deviation for prior3. The average (or mean) amount of hours spent on social media per day is 2 hours and the standard deviation is 2 hours. Calculate the z scores for the following individual scores: Person 1 (X) = 1 hour, z = Person 2 (X) = 3 hours, z= Person 3 (X) = 4 hours, z=4. A normal population has the mean of 20 and the variance of 100. A random sample of size n = 69 is selected. (a) Find the standard deviation of the sample mean. (b) How large must the sample be if you want to halve the standard deviation of the sample mean?
- Indicate whether the following sentences are true or false: (T/F) 10-Researchers only need to know how to develop certain tests, how to calculate the mean, the mode, the median or the standard deviation or chi-square, how to apply particular research techniques, but they also need to know which of these methods or techniques, are relevant and which are not, and what would they mean and indicate and why.3a) The mean IQ of 200 patients in a psychiatric hospital is 91, with a variance of 16, and the distribution is highly negatively skewed. Between what two IQ scores would we expect to find at least 160 of the patients falling? b) If the distribution was mound-shaped and symmetrical, with the same mean and standard deviation as in part A, approximately how many patients would have IQ scores at or below the 5th percentile or above a score of 97? Answers: a) 82 to 100 b) 28.5 or 29* For Questions (11)-(13): A group of 15 smokers were asked about the number of cigarettes they smoke per day. Sample data were as follows: No. of cigarettes No. of smokers 10 15 17 20 22 3 4 (11) The sample mean (a)5 (b)3 (c) 16.8 (d) 17.87 (12) The sample standard deviation (а) 3.33 (b) 11.06 (c) 3.44 (d) 11.85 (13) The sample interquartile range (b) 7 (a) 5 (c) 1 (d) 4
- Suppose the weights of 3-month-old babies are normally distributed—baby boys with a mean of 14.3 pounds and a standard deviation of 1.7, and baby girls with a mean of 12.7 pounds and a standard deviation of 1.7. What proportion of 3-month-old baby girls will weigh between 12 and 13 pounds? (Round your answer to four decimal places.)6. A comparison of life expectancy in random samples of 40 less-developed countries and 31 industrialized countries reveals the following (fictional) data. The standard deviations are significantly different from one another. Is there a significant difference in mean life expectancy between countries with these two levels of economic development? X=life expectancy of the resident at birth. Less-Developed Countries Mean=66.1 years N=40 Standard error of the difference between means=.60 Industrialized Countries Mean=76.7 years N=31Assume that a population of thousands of people whose responses were used to develop the anxiety test had scores that were normally distributed with meand of 30 and standard deviation of 10. What proportion of people in this population would have anxiety scored within the following range of scores? between 10-50.