13. The time-harmonic vector Helmholtz equations or wave equations: in a source free, lossless medium or free space in a source-free, lossy medium v’E, – B³E, = 0 v’H¸ - ß*H¸ =0 y² = joydo+jwɛ) 14. The solution of Maxwell's equations: The time-domain solution of Maxwell's equations in a source- equations in a source free, lossless free. lossy medium The time-harmonic Maxwell's medium or free space E(2,1)=(E; cos(œx – Be))Â H(2,t)=(H; cos(ex – e))§ E-E, cos Assumption: The EM wave is travelling in the +z direction.
13. The time-harmonic vector Helmholtz equations or wave equations: in a source free, lossless medium or free space in a source-free, lossy medium v’E, – B³E, = 0 v’H¸ - ß*H¸ =0 y² = joydo+jwɛ) 14. The solution of Maxwell's equations: The time-domain solution of Maxwell's equations in a source- equations in a source free, lossless free. lossy medium The time-harmonic Maxwell's medium or free space E(2,1)=(E; cos(œx – Be))Â H(2,t)=(H; cos(ex – e))§ E-E, cos Assumption: The EM wave is travelling in the +z direction.
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![13. The time-harmonic vector Helmholtz equations or wave equations:
in a source free, lossless medium
or free space
in a source-free, lossy medium
full the
V’E, – B*E¸ = 0
V°H¸ - B³H¸ = 0
y² = jmdo+ jwɛ)
also.
14. The solution of Maxwell's equations:
The time-domain solution of
The time-harmonic Maxwell's
Maxwell's equations in a source-
free. lossy medium
equations in a source free, lossless
medium or free space
E(z,1)= (E, cos(ax – B2))£
H(z,1)=(H; cos(@ – Bz))ŷ
Atr0
E=E, cos (-:) a,
Activ
Assumption: The EM wave is travelling in the +z direction.
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Transcribed Image Text:13. The time-harmonic vector Helmholtz equations or wave equations:
in a source free, lossless medium
or free space
in a source-free, lossy medium
full the
V’E, – B*E¸ = 0
V°H¸ - B³H¸ = 0
y² = jmdo+ jwɛ)
also.
14. The solution of Maxwell's equations:
The time-domain solution of
The time-harmonic Maxwell's
Maxwell's equations in a source-
free. lossy medium
equations in a source free, lossless
medium or free space
E(z,1)= (E, cos(ax – B2))£
H(z,1)=(H; cos(@ – Bz))ŷ
Atr0
E=E, cos (-:) a,
Activ
Assumption: The EM wave is travelling in the +z direction.
Go to
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