13. The position vector of a particle at time t is R = cos (t – 1) i + sinh (t – 1) j+ atk. If at t = 1, the acceleration of the particle be perpendicular to its position vector, then a is equal to (a) 0 (b) 1 1 (c) (d) JE (AMIETE, Dec. 2009) Ans. (d)
13. The position vector of a particle at time t is R = cos (t – 1) i + sinh (t – 1) j+ atk. If at t = 1, the acceleration of the particle be perpendicular to its position vector, then a is equal to (a) 0 (b) 1 1 (c) (d) JE (AMIETE, Dec. 2009) Ans. (d)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![13. The position vector of a particle at time t is R = cos (t – 1) i + sinh (t – 1) j + ark. If at t = 1,
the acceleration of the particle be perpendicular to its position vector, then a is equal to
1
(a) 0
(b) 1
(c)
2
(d)
(AMIETE, Dec. 2009) Ans. (d)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed84860d-fc5c-4aec-8cb4-d39c7e3cdd5b%2Fbb96e635-5154-4a8b-a524-2a2f9810ef60%2Fauqzkf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:13. The position vector of a particle at time t is R = cos (t – 1) i + sinh (t – 1) j + ark. If at t = 1,
the acceleration of the particle be perpendicular to its position vector, then a is equal to
1
(a) 0
(b) 1
(c)
2
(d)
(AMIETE, Dec. 2009) Ans. (d)
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