**Problem 13: Probability of Eating Fruit**Suppose that the probability that Bob eats a banana at lunch is 14%. Also, suppose that the probability that Bob eats a peach at lunch is 23%. Bob never eats both a banana and a peach at lunch. Find the probability that Bob will either eat a banana or a peach at lunch.Choices:- A. 0.37- B. 0.39- C. 0.41- D. 0.43**Explanation:**To solve this probability problem, we utilize the principle of mutually exclusive events since Bob never eats both fruits together. The total probability is the sum of the probabilities of the individual events:\[P(\text{Banana or Peach}) = P(\text{Banana}) + P(\text{Peach}) = 0.14 + 0.23 = 0.37\]Therefore, the correct answer is **A. 0.37**.

Answer - The Probability that Bob eat a banana at lunch is 14% = 0.14 The Probability…

Answered: 13. Suppose that the probability that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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13. Suppose that the probability that Bob eats a banana at lunch is 14%. Also, suppose that the probability Bob eats a peach at lunch is 23%. Bob never eats both a banana and a peach at lunch. Find the probability Bob will either eat a banana or a peach at lunch. A. 0.37 B. 0.39 C. 0.41 D. 0.43