A survey of 100 people in New York City., NY found that, The probability that they take the subway each day is 0.85. The probability that they take a taxi each day is 0.6. The probability that they take the subway and a taxi each day is 0.55. If a person is selected at random, then determine the probability that they take either the subway or a taxi each day.

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### Survey Results on Transportation Choices in New York City

A survey of 100 people in New York City, NY found the following probabilities regarding their daily transportation choices:

- The probability that they take the subway each day is 0.85.
- The probability that they take a taxi each day is 0.6.
- The probability that they take both the subway and a taxi each day is 0.55.

**Problem:**
If a person is selected at random, determine the probability that they take either the subway or a taxi each day.

**Solution:**
This is a problem of probabilities involving the union of two events. To find the probability that a person takes either the subway or a taxi, we can use the formula for the union of two events \(A\) and \(B\):

\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]

Where:
- \( P(A) \) is the probability of taking the subway,
- \( P(B) \) is the probability of taking a taxi,
- \( P(A \cap B) \) is the probability of taking both the subway and a taxi.

Given:
\[ P(A) = 0.85 \]
\[ P(B) = 0.60 \]
\[ P(A \cap B) = 0.55 \]

We can now substitute these values into the formula:

\[ P(A \cup B) = 0.85 + 0.60 - 0.55 \]
\[ P(A \cup B) = 1.45 - 0.55 \]
\[ P(A \cup B) = 0.90 \]

So, the probability that a randomly selected person takes either the subway or a taxi each day is 0.90, or 90%.
Transcribed Image Text:### Survey Results on Transportation Choices in New York City A survey of 100 people in New York City, NY found the following probabilities regarding their daily transportation choices: - The probability that they take the subway each day is 0.85. - The probability that they take a taxi each day is 0.6. - The probability that they take both the subway and a taxi each day is 0.55. **Problem:** If a person is selected at random, determine the probability that they take either the subway or a taxi each day. **Solution:** This is a problem of probabilities involving the union of two events. To find the probability that a person takes either the subway or a taxi, we can use the formula for the union of two events \(A\) and \(B\): \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Where: - \( P(A) \) is the probability of taking the subway, - \( P(B) \) is the probability of taking a taxi, - \( P(A \cap B) \) is the probability of taking both the subway and a taxi. Given: \[ P(A) = 0.85 \] \[ P(B) = 0.60 \] \[ P(A \cap B) = 0.55 \] We can now substitute these values into the formula: \[ P(A \cup B) = 0.85 + 0.60 - 0.55 \] \[ P(A \cup B) = 1.45 - 0.55 \] \[ P(A \cup B) = 0.90 \] So, the probability that a randomly selected person takes either the subway or a taxi each day is 0.90, or 90%.
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