13. Solve the given equation. (a) seca (2 sin a – v2) = 0 (b) v3 tan(3x) +1=0 (c) cos(2x) + cos(x) = 2 for x E [0, 27). (d) 4 sin?(x)+4 cos x = (e) 2 cos? x – 5 sin x – 4 = 0 for x E [0, 27). 1 for x E [0,27). 13. (а) х — + 2тп, Зт + 2nk for n, k E Z 57 (b) n for n e Z 3 x = 18 (с) х — 0 т 5т (d) x = 3 3 7п 11т т %3D (e) 6

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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13. Solve the given equation.
(a) seca (2 sin a – v2) = 0
(b) v3 tan(3x) +1=0
(c) cos(2x) + cos(x) = 2 for x E [0, 27).
(d) 4 sin?(x)+4 cos x =
(e) 2 cos? x – 5 sin x – 4 = 0 for x E [0, 27).
1 for x E [0,27).
Transcribed Image Text:13. Solve the given equation. (a) seca (2 sin a – v2) = 0 (b) v3 tan(3x) +1=0 (c) cos(2x) + cos(x) = 2 for x E [0, 27). (d) 4 sin?(x)+4 cos x = (e) 2 cos? x – 5 sin x – 4 = 0 for x E [0, 27). 1 for x E [0,27).
13. (а) х —
+ 2тп,
Зт
+ 2nk for n, k E Z
57
(b)
n for n e Z
3
x =
18
(с) х — 0
т 5т
(d) x =
3
3
7п 11т
т %3D
(e)
6
Transcribed Image Text:13. (а) х — + 2тп, Зт + 2nk for n, k E Z 57 (b) n for n e Z 3 x = 18 (с) х — 0 т 5т (d) x = 3 3 7п 11т т %3D (e) 6
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