13. For the decomposition of calcium carbonate CaCO3 (s) = CaO (s) + CO2 (g) ΔΗ175 kJ How will the amount (not concentration) of CaCO; (s) change with the following stresses to the system at equilibrium? a. CO2 (g) is removed. b. Cao (s) is added. The temperature is raised. с. d. The volume of the container is decreased.
13. For the decomposition of calcium carbonate CaCO3 (s) = CaO (s) + CO2 (g) ΔΗ175 kJ How will the amount (not concentration) of CaCO; (s) change with the following stresses to the system at equilibrium? a. CO2 (g) is removed. b. Cao (s) is added. The temperature is raised. с. d. The volume of the container is decreased.
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Chapter1: Chemical Foundations
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
Transcribed Image Text:13. For the decomposition of calcium carbonate
CACO3 (s) = CaO (s) + CO2 (g)
How will the amount (not concentration) of CaCO3 (s) change with the following stresses to
ΔΗ175 kJ
the system at equilibrium?
a. CO2 (g) is removed.
b. CaO (s) is added.
c. The temperature is raised.
d. The volume of the container is decreased.
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