#13). Find all the leart Nauares soutions of the following linear Aystem: 14 %3D Ca -4

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.2: Guassian Elimination And Matrix Methods
Problem 93E
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homework help with linear algebra, thank you! i can't get the right answer!

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### Solving Linear Systems

In this task, we are asked to find all the solutions to a given linear system. The system is represented in augmented matrix form as follows:

\[
\begin{bmatrix}
1 & 1 & -1 \\
0 & 1 & -1 \\
\end{bmatrix}
\begin{bmatrix}
c_1 \\
c_2
\end{bmatrix}
=
\begin{bmatrix}
4 \\
0
\end{bmatrix}
\]

This system can be broken down into the following linear equations:

1. \(1 \cdot c_1 + 1 \cdot c_2 = 4\)
2. \(0 \cdot c_1 + 1 \cdot c_2 = 0\)

The task is to solve these equations for the variables \(c_1\) and \(c_2\).

### Steps to Solve

1. **From the Second Equation**: Since \(0 \cdot c_1 + 1 \cdot c_2 = 0\), we have \(c_2 = 0\).

2. **Substitute \(c_2\) into the First Equation**: Substitute \(c_2 = 0\) into the first equation, \(1 \cdot c_1 + 1 \cdot 0 = 4\), which simplifies to \(c_1 = 4\).

Therefore, the solution to the system is:
- \(c_1 = 4\)
- \(c_2 = 0\)

This provides the unique solution for the given linear equations.
Transcribed Image Text:### Solving Linear Systems In this task, we are asked to find all the solutions to a given linear system. The system is represented in augmented matrix form as follows: \[ \begin{bmatrix} 1 & 1 & -1 \\ 0 & 1 & -1 \\ \end{bmatrix} \begin{bmatrix} c_1 \\ c_2 \end{bmatrix} = \begin{bmatrix} 4 \\ 0 \end{bmatrix} \] This system can be broken down into the following linear equations: 1. \(1 \cdot c_1 + 1 \cdot c_2 = 4\) 2. \(0 \cdot c_1 + 1 \cdot c_2 = 0\) The task is to solve these equations for the variables \(c_1\) and \(c_2\). ### Steps to Solve 1. **From the Second Equation**: Since \(0 \cdot c_1 + 1 \cdot c_2 = 0\), we have \(c_2 = 0\). 2. **Substitute \(c_2\) into the First Equation**: Substitute \(c_2 = 0\) into the first equation, \(1 \cdot c_1 + 1 \cdot 0 = 4\), which simplifies to \(c_1 = 4\). Therefore, the solution to the system is: - \(c_1 = 4\) - \(c_2 = 0\) This provides the unique solution for the given linear equations.
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