13. Calculate the force at member

Q: Determine the equation of the influence line for the reaction at A in the continuous beam shown in…

A: By Muller Breslau method, As we have to find the reaction at end A, hence Support at A will be…

Q: Column CD in the unbraced frame is oriented with major-axis bending and is a W12x106. Using the…

A: Direct analysis method The Direct Analysis Method originally appears as an alternative method of…

Q: y 130 mm 30 mm 30 mm -40 mm 40 mm-

A:

Q: Draw the projections (Top, Front, Side) with Dimensions for this objects

A:

Q: Determine the centroid of the shaded area shown, which is bounded bythe X axis and the parabola y? =…

A:

Q: 5. Find diameter y. All dimensions are in millimeters. 1 + 19.30 DIA 118.00 -३०

A: Tapered beam with larger diameter at AB = 19.3 mm  Length of beam ,L = 118 mm  Tapered angle = 3°…

Q: Compute Ix for the region shown. y 2 18 2-5--5- -2 -8 8. Dimensions in inches

A: The area is divided into the standard areas as shown below.

Q: Calculate the y-coordinate of the centroid of the shaded area. The triangle is equilateral.…

A:

Q: Find the centroid of the following cross-sections and planes.

A: Centrodal distanceX = 5.333 inY = 5.667 inExplanation:Step 1:Step 2:

Q: What does on the lines, 4 & 3 indicate

A: Line 3 in View 2 represents the level at which the plan or top view (View 1) is drawn. Although the…

Q: Determine the ỹ coordinate. y b. = ky? a

A:

Q: Find the centroid for the shaded area

A: Given Diagram with dimensions    To find  Centroid of the shaded area

Q: Locate the centroid 10 mm 20 mm 10 mm 10 mm 20 mm 50 mm y

A:

Q: Fo B - P 800 mm C -600 mm

A:

Q: y 500 50 80 -140- - 140- 80 60 400 500 50 500

A: Given- plate area is given  To find- centroid of given plate area

Q: 15.16 Refer to Figure 15.52. Using Michalowski's solution given in Figure 15.25 ('> 0). determine…

A: The kinematic approach of limit analysis is applied to the rigid rotational collapse mechanism by…

Q: Draw the Orthographic Projections (Top View, Front View, Side View) For the Shapes Shown Below,…

A:

Q: Q24. Draw the plan, section and elevation of the given line diagram. W BED KITCHEN W 2500x2500…

A:

Q: Determine the coordinates of the centroid of the shaded area. y | 25 E 50 60 25 60 70 50. --x 170…

A:

Q: Q1:A)Write the command to draw Figure below by using Auto CAD program (Relative Coordinate Method).…

A: question being asked here is to draw the above diagram using AUTO CAD program and also clearly…

Q: You are a professor of architecture. Show your students where the horizon line and vanishing points…

A:

Q: 31⁄5 / 4⁄7

A: 31/5=6.2 4/7=0.571

Q: ate the centroid of the shaded area. Y 20 mm 45 mm 20 mm L. 54 mm

A: To find centroid

Q: Q1: determaine the coordinates of the centeroid of the shaded area 20 40 50 20 40 30 140

A: The polar coordinate system is a method to calculate points in the system location by proper…

Q: 65 degree 6' - 17 degree 54'

A: 1 degree = 60' 65 degree 6' = 64 degree 66'

Q: +y") dx ly

A:

Q: PROBLEM 2: Determine Ix and Tx.

A: given- a plane figure to find- M.O.I  about X-axis and centroidal axis.

Q: weétermine the yalue j = 2. Det ermine the Yalue & I with Respecd to centroidal X axis =

A: 1. Value of y¯ Let 1 & 2 be the rectangle and 3 & 4 be the triangle.y¯=∑ay∑a…

Q: Q24. Draw the plan, section and elevation of the given line diagram. W BED KITCHEN 2500x2500 D…

A:

Q: Convert 36° 19' to decimal degree form.

A: Given data: θ=36∘19'

Types of Composite

Composite materials are formed by merging two components that have different chemical and physical properties. The merged output is termed as a composite, whose properties are completely different from the individual components. Composite materials also have better strength than the individual components.Composite materials usually have two main parts, reinforcement material, and matrix material. The matrix material acts as a binder and surrounds the fiber of another material that bears a much higher strength. This material is known as the reinforcement material. The matrix materials are usually high-strength additives resins, while the fibers of the reinforced material can be random, oriented, and in a mat format.Composite materials are also known as fiber-reinforced composite polymers because they are composed of the polymer matrix which is reinforced to laboratory-created fibers or naturally occurring fibers, such as glass fibers, carbon fibers, or aramid fibers. Under the application of external loads, the matrix material absorbs and transfers the loads to the fibers, these fibers in return provide good compressive strength, tensile strength, and stiffness to the fiber-reinforced composite materials.Depending upon the matrix and the reinforcement material, different properties can be induced to the fiber-reinforced composite materials, including good corrosion resistance properties. The most common matrix material is the resin while the glass fibers act as the reinforcement material. Strong fibers provide strength and stiffness to the composite materials while, a soft and flexible resin provides shape to the composite materials.