13. 2 balls collide on a pool table. The larger ball of mass 2kg experiences an acceleration of magnitude 5m/s² during the collision. What is the magnitude of the acceleration experienced by the smaller ball (mass 0.5kg) during the collision? 10 m/s? a = f-ma B) 1.25 m/s? 2(5) C) 5 m/s? - lON isa = NS D) 2.5 m/s? F az 2N N E) 20 m/s? m a

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

Two balls collide on a pool table. The larger ball of mass 2 kg experiences an acceleration of magnitude 5 m/s² during the collision. What is the magnitude of the acceleration experienced by the smaller ball (mass 0.5 kg) during the collision?

**Options:**
A) 10 m/s²  
B) 1.25 m/s²  
C) 5 m/s²  
D) 2.5 m/s²  
E) 20 m/s²  

**Solution Explanation:**

To solve this problem, we use Newton's Second Law of Motion, which states that force \( (F) \) equals mass \( (m) \) multiplied by acceleration \( (a) \), i.e., \( F = ma \).

1. **Calculate the Force on the Larger Ball:**

   Given the mass of the larger ball is 2 kg and its acceleration is 5 m/s²:

   \[
   F = 2 \, \text{kg} \times 5 \, \text{m/s}^2 = 10 \, \text{N}
   \]

2. **Calculate the Acceleration of the Smaller Ball:**

   Since the same force acts on both balls, use \( F = ma \) to find the acceleration of the smaller ball. For a smaller ball of mass 0.5 kg:

   \[
   10 \, \text{N} = 0.5 \, \text{kg} \times a
   \]

   Solving for \( a \):

   \[
   a = \frac{10 \, \text{N}}{0.5 \, \text{kg}} = 20 \, \text{m/s}^2
   \]

**Correct Answer:** E) 20 m/s²
Transcribed Image Text:**Problem Statement:** Two balls collide on a pool table. The larger ball of mass 2 kg experiences an acceleration of magnitude 5 m/s² during the collision. What is the magnitude of the acceleration experienced by the smaller ball (mass 0.5 kg) during the collision? **Options:** A) 10 m/s² B) 1.25 m/s² C) 5 m/s² D) 2.5 m/s² E) 20 m/s² **Solution Explanation:** To solve this problem, we use Newton's Second Law of Motion, which states that force \( (F) \) equals mass \( (m) \) multiplied by acceleration \( (a) \), i.e., \( F = ma \). 1. **Calculate the Force on the Larger Ball:** Given the mass of the larger ball is 2 kg and its acceleration is 5 m/s²: \[ F = 2 \, \text{kg} \times 5 \, \text{m/s}^2 = 10 \, \text{N} \] 2. **Calculate the Acceleration of the Smaller Ball:** Since the same force acts on both balls, use \( F = ma \) to find the acceleration of the smaller ball. For a smaller ball of mass 0.5 kg: \[ 10 \, \text{N} = 0.5 \, \text{kg} \times a \] Solving for \( a \): \[ a = \frac{10 \, \text{N}}{0.5 \, \text{kg}} = 20 \, \text{m/s}^2 \] **Correct Answer:** E) 20 m/s²
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