13) The following MINITAB output presents a 95% confidence interval.The assumed sigma = 9.5959%3D95% CISE MeanMeanVariable1.2187 (46.915, 51.693)49.304621.confident that the population mean is betweenFill in the blanks: We are eandB) 95%, 46.915, 51.693D) 5%, 0, 49.304A) 95%, 0, 49.304C) 5%, 46.915, 51.693

13).From the given MINITAB output the 95% confidence interval for the population mean is (46.915,…

Answered: 13) The following MINITAB output…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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9. A random sample of 25 statistics examinations was taken. The average score in the sample was 76 with a variance of 144. Assuming the scores are normally distributed, the 99% confidence interval for the population average examination score is a. 70.02 to 81.98 b. 69.82 to 82.18 C. 70.06 to 81.94 d. 69.48 to 82.52
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Compute a 95% confidence interval for the true population mean given the following 10 data that represent a sample of ceramics vessels with the following rim diameters (in centimeters), the sample mean to be x̄ = 15.3 cm and the sample standard deviation is s = 3.5 cm
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1) Construct a 94% confidence interval for the population mean, μ. Assume the population has a normal distribution.A sample of 20 part-time workers had mean annual earnings of $3120 with a standard deviation of $677. Round tothe nearest dollar. (Show work) Use TI -84 calculator.
A researcher wishes to compare the mean of time spent watching TV in a day between men and women to test if the mean watching time for men equals the mean time for women. Assume that he performed the needed test and produce the following results: Gender N Mean Standard deviation Female 116 1.95 1.51 Male 59 2.37 1.85 95% confidence Interval for (µ,-µ,):(0.79,0.94) I. Which of the following is the correct conclusion about these results using a 5% significant level? OThe mean TV watching times of men and women are equal OThere is a statistically significant difference between the mean TV watching times of men and women. OThere is not a statistically significant difference between the mean TV watching tímes of men and women. OThere is not enough information to conclude II. Which statement is correct about p-value based on your conclusion about the test? Op-value0.05 Opvalue>0.005 OCannot be determine from the information given
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1) Create a 99% confidence interval on the true standard deviation of driving speeds. Round your answer to 2 decimal places. 2) Is the assumption of normality required for this interval given that the sample size is 91?
Find the confidence interval for a Related-Samples t-test (Ch.11), given the following info: Level of confidence = 99% Before and After scores = see table below SSD (SS of the difference scores) = 2.75 Hint: as you’re doing calculations, don’t round any numbers in your calculations to less than two decimal places, or your final answer may be too rounded for you to be able to tell which answer below is correct. Person Before X1 After X2 Difference (D = X2- X1) A 15 22 +7 B 18 23 +5 C 12 17 +5 D 17 23 +6 A. 1.90 < μD < 7.18 B. 2.53 < μD < 8.02 C. 2.95 < μD < 8.55 D. 2.01 < μD < 7.58
b )part?
14. The sales price of a specific brand of cereal is believed to be normally distributed. Data were collected for a sample of 16 boxes of that brand of cereal. If the sample mean is 2 OMR and the sample standard deviation is 0.4 OMRthen the 90% confidence interval for the population mean is A. (1.8355 , 2.1645) B. (1.8040 , 2.1960) C. None D. (1.8247 , 2.1753)

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