PLS DO FAST 2 THUMBS UP WILL BE GIVEN THANK U MAKE SURE NOT TO COPY FEOM ELSE WHERE THEY ARE WRONG THX //13,RandomIfwec = fifteen kg/s× (0) = 0SensorCarlSensorhaveSo, willwall ?k/2mom212theisLKL= .001 m=mass-spring-danpurone-hundred twelve point five'N/mshownv(0) = onerundomM = = point five kypoint five m/sXx(+)Mefsensor)asmK/2612Sensor Crash into the

Given Data: To Find: Will the random sensor crash into the wall?

13, Sensor Case Randlom If So, will Sensor have Wall we c = fifteen kg/s x (0) = 0 k/2 m ว 212 is K the mass-spring-dampur = one-hundred twelve point five N/m L= .001m shown v(0) = one XX(t) M efsensor random M = as = point five ky point five m/s K/2 (12 Sensor Crash into the

13, Sensor Case Randlom If So, will Sensor have Wall we c = fifteen kg/s x (0) = 0 k/2 m ว 212 is K the mass-spring-dampur = one-hundred twelve point five N/m L= .001m shown v(0) = one XX(t) M efsensor random M = as = point five ky point five m/s K/2 (12 Sensor Crash into the

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Forced undamped vibrations

In mechanical engineering, vibration is expressed as the term that occurs due to an object's backward and forward movement about a point of equilibrium. Generally, there are three types of vibrations which are,

Question

PLS DO FAST 2 THUMBS UP WILL BE GIVEN THANK U MAKE SURE NOT TO COPY FEOM ELSE WHERE THEY ARE WRONG THX

//
13,
Random
If
we
c = fifteen kg/s
× (0) = 0
Sensor
Carl
Sensor
have
So, will
wall ?
k/2
mom
212
the
is
L
K
L= .001 m
=
mass-spring-danpur
one-hundred twelve point five'
N/m
shown
v(0) = one
rundom
M = = point five ky
point five m/s
Xx(+)
M
efsensor)
as
m
K/2
612
Sensor Crash into the

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Step 1: Write the given data and what is to find

VIEW

Step 2: Determine the equation of motion of the sensor:

VIEW

Step 3: Apply the boundary conditions to determine the generalized response:

VIEW

Step 4: Determine whether the sensor will crash into the wall:

VIEW

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VIEW

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