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13) How many oxygen atoms are contained in 2.74 g of aluminum sulfate? A) 12 B) 60 x 1023 13)

13) How many oxygen atoms are contained in 2.74 g of aluminum sulfate? A) 12 B) 60 x 1023 13)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The answer is E.) 5.79 x 10^22.
I don't know if my lack of rounding appropriate numbers is giving me incorrect answers but I'm sure I've done everything correctly.


13) How many oxygen atoms are contained in 2.74 g of aluminum sulfate? A) 12 B) 6.02 x 1023 C) 8.01 x 10-3 D) 7.22 x 1024 E) 5.79 x 1022 13)
Transcribed Image Text:13) How many oxygen atoms are contained in 2.74 g of aluminum sulfate? A) 12 B) 6.02 x 1023 C) 8.01 x 10-3 D) 7.22 x 1024 E) 5.79 x 1022 13)
look @ 23 Unit 3 Hin (cont.) (Do I need to round? and?) -2 13.) how many 0 atoms are contained in 2.74g of aluminum sulfate. A1² 504 ² A1: 26.9813386 (2) 53.9638772 22 E.) s.79x10² 5:32.065 10:13.9994 wwwwwwwww 12.74g. 1 mol: Al. 504 (1) = 32.655 g/mal (4) = 63.9776gland) * PROBLEMY (It's not 4.63 it's 4-15.49) 15.9994 63-99269_11688227-463 % g derve 15.0.8256772g/mol MAHARVARAPAREMATANDSVIN (Okay hold on... AGAIN I don't understand.) WIVAAAAM www.w hmm C 100 2.745 15³1 A1₂ 504 = convert to male, convert to mole, convert to mole convert to mole 7. 16882246 274 mand 4 moli 1 mol: A1² 504 150.0256772 que to get close to the answer I can subtract 6.022 but il must be setting it up wining. 43810 158.8256772.glimal 1 mal Al 504 4 mol: 0 do you... 2.74-1.168822746? I don't think 30 42.65776445% . why? I am 0-292205687 15.99949 1m610 n 6.2922 85687 2.74 ↓ 11.7998832% 0 50... so lost. 175.353424 158.8256772 = (180) 1.1168822746
Transcribed Image Text:look @ 23 Unit 3 Hin (cont.) (Do I need to round? and?) -2 13.) how many 0 atoms are contained in 2.74g of aluminum sulfate. A1² 504 ² A1: 26.9813386 (2) 53.9638772 22 E.) s.79x10² 5:32.065 10:13.9994 wwwwwwwww 12.74g. 1 mol: Al. 504 (1) = 32.655 g/mal (4) = 63.9776gland) * PROBLEMY (It's not 4.63 it's 4-15.49) 15.9994 63-99269_11688227-463 % g derve 15.0.8256772g/mol MAHARVARAPAREMATANDSVIN (Okay hold on... AGAIN I don't understand.) WIVAAAAM www.w hmm C 100 2.745 15³1 A1₂ 504 = convert to male, convert to mole, convert to mole convert to mole 7. 16882246 274 mand 4 moli 1 mol: A1² 504 150.0256772 que to get close to the answer I can subtract 6.022 but il must be setting it up wining. 43810 158.8256772.glimal 1 mal Al 504 4 mol: 0 do you... 2.74-1.168822746? I don't think 30 42.65776445% . why? I am 0-292205687 15.99949 1m610 n 6.2922 85687 2.74 ↓ 11.7998832% 0 50... so lost. 175.353424 158.8256772 = (180) 1.1168822746
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