Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
100%
The answer is E.) 5.79 x 10^22.
I don't know if my lack of rounding appropriate numbers is giving me incorrect answers but I'm sure I've done everything correctly.
Transcribed Image Text:13) How many oxygen atoms are contained in 2.74 g of aluminum sulfate?
A) 12
B) 6.02 x 1023
C) 8.01 x 10-3
D) 7.22 x 1024
E) 5.79 x 1022
13)
Transcribed Image Text:look @ 23
Unit 3 Hin (cont.) (Do I need to round?
and?)
-2
13.) how many 0 atoms are contained in 2.74g of aluminum sulfate. A1² 504 ²
A1: 26.9813386 (2) 53.9638772
22
E.) s.79x10²
5:32.065
10:13.9994
wwwwwwwww
12.74g. 1 mol: Al. 504
(1) = 32.655 g/mal
(4) =
63.9776gland)
* PROBLEMY (It's not 4.63 it's 4-15.49)
15.9994
63-99269_11688227-463
%
g derve
15.0.8256772g/mol
MAHARVARAPAREMATANDSVIN
(Okay hold on... AGAIN I don't understand.)
WIVAAAAM
www.w
hmm
C
100
2.745 15³1 A1₂ 504
=
convert to male, convert to mole, convert to mole convert to mole
7.
16882246
274
mand
4 moli
1 mol: A1² 504
150.0256772
que
to get close to the answer I can subtract 6.022 but
il must be setting it up wining.
43810
158.8256772.glimal 1 mal Al 504
4 mol: 0
do you... 2.74-1.168822746? I don't think 30
42.65776445%
.
why? I am
0-292205687
15.99949
1m610
n
6.2922 85687
2.74
↓
11.7998832% 0
50...
so lost.
175.353424
158.8256772
=
(180)
1.1168822746
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