13 = : Consider the circuit diagram depicted in the figure. P₂ 2.50 a E1=18 V 21/ What equation do you get when you apply the loop rule to the loop abcdefgha, in terms of the variables in the figure? If the current through the top branch is 1₂ = 0.075 A, what is the current through the bottom, 13, in amps? LR₁₂ E₂=45 V 0.5Ω ww 0.50 P $1.502

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question
: Consider the circuit diagram depicted in the figure.
13 = 1
P₂₂
2.502
F
1₂
E₁ = 18 V
21 | ²
啡
www
0.592
What equation do you get when you apply the loop rule to the loop abcdefgha, in terms of the variables in the figure?
If the current through the top branch is 12 = 0.075 A, what is the current through the bottom, 13, in amps?
1₁ P₁₂
لی
ww
E₂ = 45 V
4/2
0.52
R₂
1.52
Transcribed Image Text:: Consider the circuit diagram depicted in the figure. 13 = 1 P₂₂ 2.502 F 1₂ E₁ = 18 V 21 | ² 啡 www 0.592 What equation do you get when you apply the loop rule to the loop abcdefgha, in terms of the variables in the figure? If the current through the top branch is 12 = 0.075 A, what is the current through the bottom, 13, in amps? 1₁ P₁₂ لی ww E₂ = 45 V 4/2 0.52 R₂ 1.52
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