*13-96. Due to the constraint, the 0.5-kg cylinder C travels along the path described byr = (0.6 cos 0) m. If arm OA rotates counterclockwise with an angular velocity of 0 = 2 rad/s and an angular acceleration of 0 = 0.8 rad/s at the instant 0 = 30°, determine the force exerted by the arm on the cylinder at this instant. The cylinder is in contact with only one edge of the smooth slot, and the motion occurs in the horizontal plane. r = 0.6 cos 0- 0.3 m 0.3 m

Elements Of Electromagnetics
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*13-96. Due to the constraint, the 0.5-kg cylinder C travels
along the path described byr = (0.6 cos 0) m. If arm OA
rotates counterclockwise with an angular velocity of
e = 2 rad/s and an angular acceleration of 0 = 0.8 rad/s at
the instant 0 = 30°, determine the force exerted by the arm
on the cylinder at this instant. The cylinder is in contact with
only one edge of the smooth slot, and the motion occurs in
the horizontal plane.
r = 0.6 cos 0-
0.3 m
0, ö
0.3 m
Kinematics: Since the motion of cylinder C is known, a, and a, will be determined
first. The values of r and the time derivatives at the instant 0 = 30° are evaluated
below.
Transcribed Image Text:*13-96. Due to the constraint, the 0.5-kg cylinder C travels along the path described byr = (0.6 cos 0) m. If arm OA rotates counterclockwise with an angular velocity of e = 2 rad/s and an angular acceleration of 0 = 0.8 rad/s at the instant 0 = 30°, determine the force exerted by the arm on the cylinder at this instant. The cylinder is in contact with only one edge of the smooth slot, and the motion occurs in the horizontal plane. r = 0.6 cos 0- 0.3 m 0, ö 0.3 m Kinematics: Since the motion of cylinder C is known, a, and a, will be determined first. The values of r and the time derivatives at the instant 0 = 30° are evaluated below.
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