12FeCl2(s) + 3O2(g) → 8FeCl3(s) + 2Fe2O3(s) 1. Determine the theoretical and actual yield of Fe2O3 if 153.00 g of FeCl 2 and 12.15 g of O 2 react, and the percent yield of Fe2O3 is 61.55%. (Molar masses are FeCl2 = 126.75 g/mol, FeCl3 = 162.20 g/mol, Fe2O3 = 159.69 g/mol)

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12FeCl2(s) + 3O2(g) → 8FeCl3(s) + 2Fe2O3(s)

1. Determine the theoretical and actual yield of Fe2O3 if 153.00 g of FeCl 2 and 12.15 g of O 2 react, and the percent yield
of Fe2O3 is 61.55%. (Molar masses are FeCl2 = 126.75 g/mol, FeCl3 = 162.20 g/mol, Fe2O3 = 159.69 g/mol)
 
 
2. Consider at 4.5 M stock solution of glucose (C6H12O6, 180.156 g/mol).
(a) How many grams of glucose are needed to produced 500. mL of the stock solution.
(b) If 15.0 mL of the stock solution was diluted to a total volume of 250 mL, the concentration of the resulting solution is?
 
 
3. A solution of HClO 4 , a strong acid can be neutralized by adding solid Cu(OH)2 .
(a) Write the net ionic equation describing the reaction between HClO4 , and Cu(OH)2
(b) How many grams of Cu(OH)2 are needed to neutralize 25.0 mL of 0.500 M HClO 4 ,? 
 
 
4.When 75.0 mL of 0.455 M Al(NO 3 )2 and 110 mL of 0.312 M Na2 CO3 are mixed a precipitate forms.
(a) Write the net ionic equation describing the formation of the precipitate
(b) What is the (theoretical) mass of the precipitate that forms?
 
 
 
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