128 of all Americans live in poverty. If 31 Americans are randomly selected, find the probability thata. Exactly 2 of them live in poverty.b. At most 4 of them live in poverty.c. At least 2 of them live in poverty.d. Between 3 and 10 (including 3 and 10) of them live in poverty.Round each answer to 4 decimal places.Question Help: O Video e Written Example> Next QuestionMacBook AirDIIDD8088F5F6F7F8F9F10F1F2F3F4!@#$&*12346.78.9.QWERYADFHJCVcommandoptintroloptioncommand.. .-* 00

Let X be the random variable from binomial distribution with probability (p)= 12% = 0.12 and sample…

Answered: 128 of all Americans live in poverty.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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128 of all Americans live in poverty. If 31 Americans are randomly selected, find the probability that a. Exactly 2 of them live in poverty. b. At most 4 of them live in poverty. c. At least 2 of them live in poverty.