128 of all Americans live in poverty. If 31 Americans are randomly selected, find the probability thata. Exactly 2 of them live in poverty.b. At most 4 of them live in poverty.c. At least 2 of them live in poverty.d. Between 3 and 10 (including 3 and 10) of them live in poverty.Round each answer to 4 decimal places.Question Help: O Video e Written Example> Next QuestionMacBook AirDIIDD8088F5F6F7F8F9F10F1F2F3F4!@#$&*12346.78.9.QWERYADFHJCVcommandoptintroloptioncommand.. .-* 00

Let X be the random variable from binomial distribution with probability (p)= 12% = 0.12 and sample…

Answered: 128 of all Americans live in poverty.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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9% of all Americans live in poverty. If 36 Americans are randomly selected, find the probability that a. Exactly 3 of them live in poverty. b. At most 3 of them live in poverty. c. At least 5 of them live in poverty. d. Between 2 and 10 (including 2 and 10) of them live in poverty. 74% of all Americans live in cities with population greater than 100,000 people. If 49 Americans are randomly selected, find the probability that a. Exactly 35 of them live in cities with population greater than 100,000 people. b. At most 35 of them live in cities with population greater than 100,000 people. c. At least 36 of them live in cities with population greater than 100,000 people. d. Between 29 and 33 (including 29 and 33) of them live in cities with population greater than 100,000 people. 77% of all students at a college still need to take another math class. If 36 students are randomly selected, find the probability that a. Exactly 27 of them need to take another math class. b. At most 27…
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128 of all Americans live in poverty. If 31 Americans are randomly selected, find the probability that a. Exactly 2 of them live in poverty. b. At most 4 of them live in poverty. c. At least 2 of them live in poverty.