10% of all Americans live in poverty. If 47 Americans are randomly selected, find the probability that a. Exactly 3 of them live in poverty. b. At most 5 of them live in poverty. c. At least 2 of them live in poverty.
10% of all Americans live in poverty. If 47 Americans are randomly selected, find the probability that a. Exactly 3 of them live in poverty. b. At most 5 of them live in poverty. c. At least 2 of them live in poverty.
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter7: Percents
Section7.1: Percents And Fractions
Problem 30E
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![10% of all Americans live in poverty. If 47 Americans are randomly selected, find the probability that
a. Exactly 3 of them live in poverty.
b. At most 5 of them live in poverty.
c. At least 2 of them live in poverty.
d. Between 2 and 9 (including 2 and 9) of them live in poverty.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F550e8ebf-4619-4f5d-9425-76b7522cedec%2F24c3d8e2-1a84-4bb0-b827-b629b245fcfa%2Fk468dvm_processed.png&w=3840&q=75)
Transcribed Image Text:10% of all Americans live in poverty. If 47 Americans are randomly selected, find the probability that
a. Exactly 3 of them live in poverty.
b. At most 5 of them live in poverty.
c. At least 2 of them live in poverty.
d. Between 2 and 9 (including 2 and 9) of them live in poverty.
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