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12/2/h FC d=1h - th= — h 끝 4m fentroid -center of pressure. water F₁ 34h 7 F₂ H Jade (36 =0.586) Solve for He H= (1) How deep should the oil be N 0.8E 4.31M so that there is no net horizontal force on the plate? He 16 M₁ = F₁-d₁ = (@hc, A₁) d₁ M₂ = F₂ • d == (J₂k₁₂ A₁₂ ) d₂ F₁ = F₂ P. (B-4m) = P² (E. H) · 4 = H 1 (4) 4H). H 16 = 0.86 H (2) Are the magnitudes of the moments about the base of the plate equal? Wh Why? 2 =

12/2/h FC d=1h - th= — h 끝 4m fentroid -center of pressure. water F₁ 34h 7 F₂ H Jade (36 =0.586) Solve for He H= (1) How deep should the oil be N 0.8E 4.31M so that there is no net horizontal force on the plate? He 16 M₁ = F₁-d₁ = (@hc, A₁) d₁ M₂ = F₂ • d == (J₂k₁₂ A₁₂ ) d₂ F₁ = F₂ P. (B-4m) = P² (E. H) · 4 = H 1 (4) 4H). H 16 = 0.86 H (2) Are the magnitudes of the moments about the base of the plate equal? Wh Why? 2 =

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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h 4m Zd d = h - th= th ? fentroid - center of pressure. water F₁ 3h F₂ =0.86) 7 M₁ = F₁-d₁ = @h²₁ A₁) d₁ M₂= F₂ · d ₂ (J₂h²₁₂A₂) d₂ H Solve for Ha № 0.86 =431m (1) How deep should the oil be So that there is no net horizental force on the platte? H= [16 F₁ = F₂ P₁ (B⋅4m) = P₂|(B⋅H) That=rcha - H 1 (m) - 4MH). H x4m 16 = 0.86 H² (2) Are the magnitudes of the moments about "the base of the plate equal ? Why?
Transcribed Image Text:h 4m Zd d = h - th= th ? fentroid - center of pressure. water F₁ 3h F₂ =0.86) 7 M₁ = F₁-d₁ = @h²₁ A₁) d₁ M₂= F₂ · d ₂ (J₂h²₁₂A₂) d₂ H Solve for Ha № 0.86 =431m (1) How deep should the oil be So that there is no net horizental force on the platte? H= [16 F₁ = F₂ P₁ (B⋅4m) = P₂|(B⋅H) That=rcha - H 1 (m) - 4MH). H x4m 16 = 0.86 H² (2) Are the magnitudes of the moments about "the base of the plate equal ? Why?
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