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12:23 PM p >> ← + 46.34 AC Expert Help Maths Science M 11:11 when 8.28gram of ethand was heated with 60gram of the noic acid 49.76 of the acid remain at equilibrium, Calcate the value Kc, i) what mass of ethyl ethenate should le present in the equilbrum mixture formed from 13.89am of ethanol and 12 gram of etanoic acids (C = 12, 0=16, H = 1) when 8.28gram of ethanol was heated with 60gram of the noic acid, 49.76. of the acid remain at equilibrium, Calculato the value Kc, i) what mass ov ethyl ethenDate shouldly present in the equilbrum mixture formed from 13.89am of ethanol and 12 gram of etanoic acids (C = 12, 0=16, H = 1) ● STEP BY STEP SOLUTION 1 Analyze Calculate the moles of ethanol and ethanoic acid initially. 1. Moles of ethanol (C2H5OH): Molecular weight x ethanol = 2 × 12+ 6 × 1+1 × 16 = 46 g, Moles of ethanol 8.28 g 46 g/mol 0.18 mol

12:23 PM p >> ← + 46.34 AC Expert Help Maths Science M 11:11 when 8.28gram of ethand was heated with 60gram of the noic acid 49.76 of the acid remain at equilibrium, Calcate the value Kc, i) what mass of ethyl ethenate should le present in the equilbrum mixture formed from 13.89am of ethanol and 12 gram of etanoic acids (C = 12, 0=16, H = 1) when 8.28gram of ethanol was heated with 60gram of the noic acid, 49.76. of the acid remain at equilibrium, Calculato the value Kc, i) what mass ov ethyl ethenDate shouldly present in the equilbrum mixture formed from 13.89am of ethanol and 12 gram of etanoic acids (C = 12, 0=16, H = 1) ● STEP BY STEP SOLUTION 1 Analyze Calculate the moles of ethanol and ethanoic acid initially. 1. Moles of ethanol (C2H5OH): Molecular weight x ethanol = 2 × 12+ 6 × 1+1 × 16 = 46 g, Moles of ethanol 8.28 g 46 g/mol 0.18 mol

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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12:23 PM p >> ← + 46.34 AC Expert Help Maths Science M 11:11 when 8.28gram of ethand was heated with 60gram of the noic acid 49.76 of the acid remain at equilibrium, Calcate the value Kc, i) what mass of ethyl ethenate should le present in the equilbrum mixture formed from 13.89am of ethanol and 12 gram of etanoic acids (C = 12, 0=16, H = 1) when 8.28gram of ethanol was heated with 60gram of the noic acid, 49.76. of the acid remain at equilibrium, Calculato the value Kc, i) what mass ov ethyl ethenDate shouldly present in the equilbrum mixture formed from 13.89am of ethanol and 12 gram of etanoic acids (C = 12, 0=16, H = 1) ● STEP BY STEP SOLUTION 1 Analyze Calculate the moles of ethanol and ethanoic acid initially. 1. Moles of ethanol (C2H5OH): Molecular weight x ethanol = 2 × 12+ 6 × 1+1 × 16 = 46 g, Moles of ethanol 8.28 g 46 g/mol 0.18 mol
Transcribed Image Text:12:23 PM p >> ← + 46.34 AC Expert Help Maths Science M 11:11 when 8.28gram of ethand was heated with 60gram of the noic acid 49.76 of the acid remain at equilibrium, Calcate the value Kc, i) what mass of ethyl ethenate should le present in the equilbrum mixture formed from 13.89am of ethanol and 12 gram of etanoic acids (C = 12, 0=16, H = 1) when 8.28gram of ethanol was heated with 60gram of the noic acid, 49.76. of the acid remain at equilibrium, Calculato the value Kc, i) what mass ov ethyl ethenDate shouldly present in the equilbrum mixture formed from 13.89am of ethanol and 12 gram of etanoic acids (C = 12, 0=16, H = 1) ● STEP BY STEP SOLUTION 1 Analyze Calculate the moles of ethanol and ethanoic acid initially. 1. Moles of ethanol (C2H5OH): Molecular weight x ethanol = 2 × 12+ 6 × 1+1 × 16 = 46 g, Moles of ethanol 8.28 g 46 g/mol 0.18 mol
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