1=2.5 m/s A 4500 kg truck is stuck at the bottom of a ditch. A winch 30° (small motor attached to a cable) cable is attached to a tree at the top of the ditch, and used to extract the truck. The winch puts out a constant power of 2.05 kW, the ditch slopes up at 30° from the horizontal, the truck is accelerated from 0.0 to 2.5 m/s during the extraction, and the coefficient of kinetic friction between the truck and the ground is 0.56. How long does it take to drag the truck up to a height of h = 2.65 m above the bottom of the ditch? Note: ignore any energy needed to rotate the truck, (1446)

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Question 14
1,= 2.5 m s
A 4500 kg truck is stuck at the bottom of a ditch. A winch
V =0
h
30°
(small motor attached to a cable) cable is attached to a tree at the top of the ditch, and used to extract the truck. The winch puts out a constant
of 2.05 kW, the ditch slopes up at 30° from the horizontal, the truck is accelerated from 0.0 to 2.5 m/s during the extraction, and the
power
coefficient of kinetic friction between the truck and the ground is 0.56. How long does it take to drag the truck up to a height of h = 2.65 m
above the bottom of the ditch? Note: ignore any energy needed to rotate the truck. (1446)
%3D
Transcribed Image Text:Question 14 1,= 2.5 m s A 4500 kg truck is stuck at the bottom of a ditch. A winch V =0 h 30° (small motor attached to a cable) cable is attached to a tree at the top of the ditch, and used to extract the truck. The winch puts out a constant of 2.05 kW, the ditch slopes up at 30° from the horizontal, the truck is accelerated from 0.0 to 2.5 m/s during the extraction, and the power coefficient of kinetic friction between the truck and the ground is 0.56. How long does it take to drag the truck up to a height of h = 2.65 m above the bottom of the ditch? Note: ignore any energy needed to rotate the truck. (1446) %3D
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