12.2 g of 2-methylbutan-2-ol (MW 88.15 g/mol) reacts with excess H2SO4 to form 7.98 g of 2-methylbut-2-ene (MW 70.13 g/mol). Calculate the %-yield of the 2-methylbut-2- ene product. NOTE! Report your answer as a WHOLE # and exclude the %-sign from your answer. Type vour answer

Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter21: Hydrocarbons
Section: Chapter Questions
Problem 91A
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12.2 g of 2-methylbutan-2-ol (MW 88.15 g/mol) reacts with excess H2SO4 to form 7.98 g of 2-methylbut-2-ene (MW 70.13 g/mol). Calculate the %-yield of the 2-methylbut-2-
ene product. NOTE! Report your answer as a WHOLE # and exclude the %-sign from your answer.
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Transcribed Image Text:12.2 g of 2-methylbutan-2-ol (MW 88.15 g/mol) reacts with excess H2SO4 to form 7.98 g of 2-methylbut-2-ene (MW 70.13 g/mol). Calculate the %-yield of the 2-methylbut-2- ene product. NOTE! Report your answer as a WHOLE # and exclude the %-sign from your answer. Type your answer... Submit
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