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For the reaction shown below, 2.00 mL of a 2.00 M solution of bromine, 562 mg of alkene reactant, and excess acetic acid are used to obtain 322 mg of brominated product. What is the percent yield of brominated product?     Bromine MW = 159.81 g/mol; Alkene reactant MW = 134.22 g/mol; Acetic acid MW = 60.05 g/mol; Brominated product MW = 328.04 g/mol

For the reaction shown below, 2.00 mL of a 2.00 M solution of bromine, 562 mg of alkene reactant, and excess acetic acid are used to obtain 322 mg of brominated product. What is the percent yield of brominated product?     Bromine MW = 159.81 g/mol; Alkene reactant MW = 134.22 g/mol; Acetic acid MW = 60.05 g/mol; Brominated product MW = 328.04 g/mol

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.94QP
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For the reaction shown below, 2.00 mL of a 2.00 M solution of bromine, 562 mg of alkene reactant, and excess acetic acid are used to obtain 322 mg of brominated product. What is the percent yield of brominated product?

   

Bromine MW = 159.81 g/mol; Alkene reactant MW = 134.22 g/mol;
Acetic acid MW = 60.05 g/mol; Brominated product MW = 328.04 g/mol

 

Br. Br Br2 ACOH Br Br
Transcribed Image Text:Br. Br Br2 ACOH Br Br
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