12. IQ and Lead Exposure Data Set 7 "IQ and Lead" in Appendix B lists full IQ scores fora random sample of subjects with low lead levels in their blood and another random sample ofsubjects with high lead levels in their blood. The statistics are summarized below.a. Use a 0.05 significance level to test the claim that the mean IQ score of people with lowblood lead levels is higher than the mean IQ score of people with high blood lead levels.b. Construct a confidence interval appropriate for the hypothesis test in part (a).c. Does exposure to lead appear to have an effect on IQ scores?Low Blood Lead Level: n = 78,7 = 92.88462, s = 15.34451High Blood Lead Level: n = 21, x = 86.90476, s= 8.988352

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Answered: 12. IQ and Lead Exposure Data Set 7 "IQ…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I often hear the opinion that "people who listen to classical music are smarter". In an attempt to test that claim, I gave an IQ test to two groups of people: Group 1: Students who primarily listen to non-classical music. Group 2: Students who primarily listen to classical music. Their scores are summarized in the following table: Std. Deviation Group 1 111 Group 2 100 98 87 119 108 102 110 10.392 85 105 97 114 93 101 9.142 Answer the question using a 0.10 level of significance. Select the correct answer to this question: Which distribution would the Test Statistic for this test come from? O F
Section 11.2 Question #6 The table below summarizes data from a survey of a sample of women. Using a 0.05 significance level, and assuming that the sample sizes of 700 men and 300 women are predetermined, test the claim that the proportions of agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does it appear that the gender of the interviewer affected the responses of women? Gender of Interviewer Man Woman Women who agree 422 257 Women who disagree 278 43 View the chi-square distribution table. Chi-square distribution table Dialog content starts Area to the Right of the Critical Value Degrees of Freedom 0.995 0.99 0.975 0.95 0.90 0.10 0.05 0.025 0.01 0.005 1 - - 0.001 0.004 0.016 2.706 3.841 5.024 6.635 7.879 2 0.010 0.020 0.051 0.103 0.211 4.605…
2. The lengths (in feet) of a random sample of suspension bridges in the United States, Europe, and Asia are shown. At a 0.05, is there sufficient evidence to conclude that there is a difference in mean lengths? United States Europe Asia 4260 5238 6529 3500 4626 4543 2300 4347 3668 2000 3300 3379 1850 2874
Consider the following set of data:Suppose the test statistic turned out to be z = -1.20 (not the correct value). Find a two-tailed p-value for this test statistic. Select one: A. p-value = .6151 B. p-value = .3849 C. p-value = .2302 D. p-value = .1151
Consider the example from the previous problem, in part (b). The sizes (in grams) of Latavia's 14 oranges are 124, 126, 129, 130, 134, 136, 139, 142, 146, 149, 152, 154, 155, and 157 g. a. Find the sample mean of Latavia's data. b. Make a boxplot or a histogram of Latavia's data with a bin size of 10. c. If even a small sample is graphed and has no major skew or outliers, it is generally reasonable to assume that the population “could reasonably be normal," and therefore that the sampling distribution of the mean is approximately normal. This is the "normal population" condition. Does this sample appear to satisfy this condition? d. Latavia reads online that medium-sized navel oranges have a mean mass of 131 g with a standard deviation of 18 g. She is interested to test if the Fresh Foods oranges match those parameters. State a null and alternative hypothesis for this situation using symbols. Note that Latavia is making two assumptions in her test. e. Calculate a test statistic: what…
The Nielson Home Technology Report provided information about home technology and cell phone usage. The following data are the hours of daily cell phone usage for a random sample of college students. Hours of Relative Usage Frequency Frequency 0.0-> 2.9 5 3.0- 5.9 28 6.0- 8.9 8 9.0-> 11.9 6 12.0- 14.9 3 Find the relative frequency of college students who use their cell phone between 12.0 and 14.9 hours. a.0.30 b.0.12 Oc. 0.06 d.0.03
The Economist collects data each year on the price of a Big Mac in various countries around the world. The price of a Big Mac for a sample of McDonalds restaurants in Europe in May 2009 resulted in the following Big Mac prices (after conversion to U.S. dollars):3.80 5.89 4.92 3.88 2.65 5.57 6.39 3.24The mean price of a Big Mac in the U.S. in May 2009 was $3.57. For purposes of this exercise, assume it is reasonable to regard the sample as representative of European McDonalds restaurants. Does the sample provide convincing evidence that the mean May 2009 price of a Big Mac in Europe is greater than the reported U.S. price? Test the relevant hypotheses using a = .05. Assume a normal distribution of the data. x = Ho: μ = Ha: Select an answer α= P-value = |: S= Based on the above we choose Question Help: Post to foru Submit Question (Put in the correct symbol and value) ✓ Select an answer Reject the null hypothesis Fail to reject the null hypothesis
The researcher believes that happy workers are more productive workers. So he administers a job satisfaction scale to 100 randomly selected workers at his company. He also gets measures of their work productivity from the HR department (number of customers served). What is the researcher’s alternative hypothesis? a. There will be a difference between job satisfaction and worker productivity. b. The correlation between job satisfaction and worker productivity will be greater than zero. c. The most satisfied workers will be less likely to leave the company. d. There will be no relationship between job satisfaction and worker productivity.
For a sample whose observations, 5, 12, 3, 7, 11, 1, 85, 5, 9, and 5, represent the number of medical leaves claimed by 10 employees of a company in a year, which of the following appears to be the best measure of the center of the data? O mean none of these O mode O median
d. what decision can you make and what does that mean? e. what type of error could you be making and what does that mean f. report results in apa format
This question will be answered in three parts. Use the following sample data of math test scores to answer all three parts: 43; 55; 54; 83; 95; 58; 85; 65; 72; 96; 71; 47; 71; 82 Part A) Calculate the mean for the data above: Round your answer to 2 decimal places.
The mean birthweight of an infant is thought to be associated with the smoking status of the mother during the first trimester of the pregnancy. Consider the following data from mothers divided into four categories according to smoking habits, and the corresponding birthweights of their children. Group 1: Mother is a non smoker (NON): 7.5, 6.2, 6.9, 7.4, 9.2, 8.3, 7.6 Group 2: Mother is an ex-smoker (EX): 5.8, 7.3, 8.2, 7.1, 7.8 Group 3: Mother is a current smoker, smokes less than 1 pack per day (CUR < 1) 5.9, 6.2, 5.8, 4.7, 8.3, 7.2, 6.2 Group 4: Mother is a current smoker, smokes more than or equal to 1 pack per day (Cur ≥ 1) 6.2, 6.8, 5.7, 4.9, 6.2, 7.1, 5.8, 5.4 Using Stata test whether or not the mean birthweights are equal across all four groups at the alpha = 0.05 level. What is the corresponding p-value? O 0.0284 0.0137 O 0.05 O 0.737

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