12. An engineer must choose between two technically equivalent alternatives, A and B. Based upon the data in the table below and an interest rate of 9%, which alternative should be selected? A B $3,000 $6,000 $500 $300 First Cost Annual Maintenance End of Useful Life Salvage Value $700 $1,000 15 Useful Life years years O a. Choose A; we want to maximize the costs O b. Choose B; we want to minimize the costs Oc. Choose A; we want to minimize the costs O d. Choose B; we want to maximize the costs O e.I don't wanna choose
12. An engineer must choose between two technically equivalent alternatives, A and B. Based upon the data in the table below and an interest rate of 9%, which alternative should be selected? A B $3,000 $6,000 $500 $300 First Cost Annual Maintenance End of Useful Life Salvage Value $700 $1,000 15 Useful Life years years O a. Choose A; we want to maximize the costs O b. Choose B; we want to minimize the costs Oc. Choose A; we want to minimize the costs O d. Choose B; we want to maximize the costs O e.I don't wanna choose
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:12. An engineer must choose between two technically equivalent
alternatives, A and B. Based upon the data in the table below and an
interest rate of 9%, which alternative should be selected?
A B
$3,000 $6,000
$500
First Cost
Annual Maintenance
$300
End of Useful Life Salvage
Value
$700
$1,000
15
Useful Life
years years
a. Choose A; we want to maximize the costs
O b. Choose B; we want to minimize the costs
O c. Choose A; we want to minimize the costs
O d. Choose B; we want to maximize the costs
O e. I don't wanna choose
O other:
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